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3 years ago

Which part of a hypothesis should the student add to this that could also be tested in other experiments?

Chemistry

2 answers:

Fittoniya [83]3 years ago

6 0

Answer:

an explanation based on prior scientific knowledge or observations

Explanation:

Nat2105 [25]3 years ago

5 0

If and then statement

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What is the composition of Gilsonite?

nekit [7.7K]

Answer:

Roughly C100 H140 N3 O

Explanation:

Gilsonite is a bituminous product that resembles shiny black obsidian.

It contains more than 100 elements.

Its mass composition varies but is approximately 84 % C, 10 % H, 3 % N, and 1 % O.

Its empirical formula is roughly C100 H140 N3 O.

3 0

3 years ago

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

2 years ago

a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is

NeX [460]

Answer:

The specific heat of iron is 0.45 J/g.°C

Explanation:

The amount of heat absorbed by the metal is given by:

heat = m x Sh x ΔT

From the data, we have:

heat = 180.8 J

mass = m = 22.44 g

ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C

Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT) = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

8 0

2 years ago

Pure substance can be __ and __

Aleksandr [31]

It can be an element or a compound

4 0

3 years ago

A compound is composed of 13% carbon, 4.3% hydrogen, 30.4% nitrogen, and 52.2% oxygen. The mystery compound has a molar mass of

vredina [299]

Answer:

C₂H₈N₄O₆ is the molecular formula for the compound

Explanation:

Data from the problem:

13 g of C in 100 g of compound

4.3 g of H in 100 g of compound

30.4 g of N in 100 g of compound

52.2 g of O in 100 g of compound

Firstly we determine, the mass of each in 184 g of compound, which is 1 mol

(13 g / 100 g) . 184 g = 24 g C

(4.3 g / 100 g) . 184 g = 7.91 g H ≅ 8 g H

(30.4 g / 100 g) . 184 g = 56 g N

(52.2 g / 100 g) . 184 g = 96 g O

And now, we divide the mass by the molar mass of each to determine the moles:

24 g C / 12 g/mol = 2 mol C

8g H / 1 g/mol = 8 mol H

56 g N / 14 g/mol = 4 mol N

96 g O / 16 g/mol = 6 mol O

So the molecular formula of the compound is C₂H₈N₄O₆

8 0

3 years ago