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lidiya [134]
3 years ago
15

How does floating ice affect you in the world you live in? PLZ EXPLAIN

Chemistry
2 answers:
melisa1 [442]3 years ago
6 0
It is asking how floating ice would affect you in the world you live on (obviously) but in the sense that you don’t live near an ocean the biggest impact of floating ice is the ice in your water. If you were to be on a ship or near a colder ocean, then icebergs would affect you in that way.
Sholpan [36]3 years ago
3 0

Water is one of the few substances which expand in volume when frozen, compared to liquid. Usually substances condense when cooled, but at the point of freezing, when liquid water becomes solid ice, the molecules lock into a matrix in which there is more space between molecules - ice expands! This is why ice floats on liquid water.

It is this miracle which has shaped the planet and allowed life to thrive. Expansion of ice is responsible for much land-shaping erosion on land, the heaving off of boulders from mountain tops. And the floating of ice on lakes, rivers and oceans - if the frozen water was indeed more dense than liquid water, it would sink and pile up in the cold depths. There would be no life thriving under the ice, overwintering. It would all eventually freeze solid, and all the life forms with it.

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1. Imagine you have a sealed 20.0 L balloon filled with helium gas at 750 mmHg in the
SVETLANKA909090 [29]

Answer:

17.6510 L

Explanation:

First we should get the number of moles of helium here by Boyle's law

PV=nRT

P=750/760= 0.9868 atm

T=25+273=298 kelvin

R= 0.08206

V= 20L

so

n=PV/RT

n=0.9868×20/0.08206×298

n=0.80707 mol

Then use the same law

V=0.80707×0.08206×263/0.9869=

17.6510L

SO THE VOLUME WILL BE 17.6510 L

6 0
2 years ago
The solubility of carbon dioxide in water is 0.161 g CO2in 100 mL of water at 20ºC and 1.00 atmCO2. A soft drink is carbonated w
Sedbober [7]

<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of carbon dioxide

C_2\text{ and }p_2 are the final concentration and partial pressure of carbon dioxide

We are given:

C_1=0.161g/100mL\\p_1=1.00atm\\C_2=?\\p_2=5.50atm

Putting values in above equation, we get:

\frac{0.161g/100mL}{C_2}=\frac{1.00atm}{5.50atm}\\\\C_2=\frac{0.161g/100mL\times 5.50atm}{1.00atm}=0.886g/100mL

Hence, the solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

4 0
4 years ago
Jose wandered 4 kilometers at 2 kilometers per hour. How long did jose wnader?
Anton [14]
8 kilometer? is that right or explain to me pls.
7 0
3 years ago
Use the name to write the formula for the following ionic compound: scandium (III) hydroxide
asambeis [7]

Answer:

.

Explanation:

.

6 0
2 years ago
A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown c
lutik1710 [3]
1.50 M concentration. Hope you are happy
5 0
3 years ago
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