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KonstantinChe [14]

3 years ago

9

A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown c

oncentration. What is the concentration of the sulfuric acid?
PLEASE HELP ME, I WILL MAKE YOU BRAINLEST ANSWER!!!!!!!!!!

1 answer:

lutik1710 [3]3 years ago

5 0

1.50 M concentration. Hope you are happy

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Arada [10]

Answer:

The answer is NO

Explanation:

In every compound, the sum of oxidation number between the elements is 0.

In NO, nitrogen acts with +2 and oxygen as usual acts with -2
In N₂O₃, nitrogen acts with +3 and oxygen, -2
In NO₂, nitrogen acts with +4, and oxygen -2
In N₂O, nitrogen acts with +1, and oxygen -2

8 0

3 years ago

How many molecules are in 9.45 moles ? ( NaNO3)

Rzqust [24]

Answer:

There are 5.69*10²⁴ molecules in 9.45 moles.

Explanation:

The mole is defined as the amount of matter that particles have, that is, atoms and elementary entities.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

Then the following rule of three can be applied: if 1 mole contains 6.023 * 10²³ molecules, 9.45 moles, how many molecules will it have?

$amount of molecules=\frac{9.45 moles*6.023*10^{23}molecules }{1 mole}$

Solving:

amount of molecules= 5.69*10²⁴⁴ molecules

<u><em>There are 5.69*10²⁴ molecules in 9.45 moles.</em></u>

8 0

2 years ago

A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl

diamong [38]

<u>Answer:</u>

<u>For A:</u> The average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u> The rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

<u>Explanation:</u>

<u>For A:</u>

The average molecular speed of the gas is calculated by using the formula:

$V_{gas}=\sqrt{\frac{8RT}{\pi M}}$

OR

$V_{gas}\propto \sqrt{\frac{1}{M}}$

where, M is the molar mass of gas

Forming an equation for the two gases:

$\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}$ .....(1)

Given values:

$V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol$

Plugging values in equation 1:

$\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s$

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u>

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

$Rate\propto \frac{1}{\sqrt{M}}$

Where, M is the molar mass of the gas

Forming an equation for the two gases:

$\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}$ .....(2)

Given values:

$Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol$

Plugging values in equation 2:

$\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr$

Hence, the rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

8 0

2 years ago

What’s the effect of drinking on the digestive system?

AveGali [126]

Alcohol consumption can damage the digestive system and can increase the risk of alcohol-caused cancer and liver disease.

3 0

3 years ago

zepelin [54]

The answer is b 592 L

7 0

2 years ago