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dsp73
3 years ago
14

In order to determine the oil content of different types of potato crisps (chips), a student weighed 5.00g of crushed crisps and

mixed them with 20.0cm3 of non-polar solvent.
She assumed all the oil in the crisps dissolved in the solvent.
The student then filtered the mixture to remove any solids, and gently heated the solution on a hot plate to evaporate the solvent.
She measured the mass of the oil that remained from each type of crisps
Suggest why a non-polar solvent was needed.
Chemistry
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:

In order to determine the oil content of different types of potato crisps (chips), a student weighed 5.00 g of crushed crisps and mixed them with 20.0 cm3 of non-polar solvent. She assumed all the oil in the crisps dissolved in the solvent. The student then filtered the mixture to remove any solids, and gently heated the solution ...

Explanation:

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We have the relation

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\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}

Comparing the exponents we get

1=n-1\\\Rightarrow n=2

The order of the reaction is 2.

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