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3 years ago

How do you find acceleration

Physics

2 answers:

tatyana61 [14]3 years ago

5 0

Answer:

Acceleration is given by the formula :

a = (v - u)/t

a is the acceleration , u is the initial velocity , v is the final velocity , t is the time in seconds

erastova [34]3 years ago

3 0

Acceleration=non-uniform velocity/time
=displacement/time^2

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3 years ago

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The acceleration due to gravity is lower on the Moon than on Earth. Which of the following is true about the mass and weight of

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Mass is the same, weight is less

<h3>What is the Weight and mass on Moon ?</h3>

As we know that the mass of the object is the measurement of the quantity of the matter that is present in it

So here we can say that if the mass of the object is m then its total quantity of the matter that is present in it is given as

mass = (density) × (volume)

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2 years ago

A 1.80-kg monkey wrench is pivoted 0.250 m from its center of mass and allowed to swing as a physical pendulum. The period for s

Evgen [1.6K]

Answer:

(a) I (Moment of inertia)=0.0987 $kgm^{2}$

(b) W(Angular Speed)=2.66 $\frac{rad}{s}$

Explanation:

Given data

m (Monkey mass)= 1.80 kg

d=2.50 m

T (Time Period)=0.940 s

Angle= 0.400 rad

(a) I (Moment of Inertia)=?

(b) W (Angular Speed)=?

For part (a) I (Moment of Inertia)=?

Time Period Formula is given as

$T=2(3.14)\sqrt{\frac{I}{mgd} }$

After Simplifying we get

$I=\frac{mgdT^{2} }{4*(3.14)^{2}}$

$I=\frac{1.8*9.8*0.25*(0.94)^{2} }{4(3.14)^{2} }$

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For Part (b) Angular Speed

From Kinetic Energy we get

$KE=\frac{1}{2}IW^{2}$

Pontential Energy

$PE=mgd(1-Cosa)$

KE=PE

$\frac{1}{2}IW^{2}=mgd(1-Cosa)$

$W^{2}=\frac{2mgd(1-Cosa)}{I}$

$W=\sqrt{\frac{2*1.8*9.8*0.25*(1-Cos(0.4)rad)}{0.0987} }$

$W=2.66\frac{rad}{s}$

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3 years ago