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sdas [7]
3 years ago
15

If A, B, and C are three activities connected with SS and FF (combination) relationships with 2-day lag on SS relationship only.

Their durations are 5, 10, and 3 respectively. What is the duration of the project?a. 5 days. b. 10 days. c. 3 days. d 18 days.
Physics
1 answer:
tia_tia [17]3 years ago
5 0

Answer:

B. 10 days

Explanation:

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Read 2 more answers
The clothes washer in your house consumes 470 kWh of energy per year. Price of the washer is $360 and the lifetime of the washer
VashaNatasha [74]

Answer:

$893

Explanation: the complete question should be

The clothes washer in your house consumes 470 kWh of energy per year. Price of the washer is $360 and the lifetime of the washer is 10 yrs. Energy price in your city is 9 cents per kWh. What is the lifecycle cost of the clothes washer? (assume a maintenance cost of $11 per year)

SOLUTION

Given:

The clothes washe power consumption (PC) is 470 kWh

Price of the washer (P) is $360

lifetime of the washer (L) is 10 yrs

Energy price in the city (E) is 9 cents per kWh (Covert to $ by dividing 100)

maintenance cost (M) is $11 per year

Lifecycle cost = P + (PC × L × E) +M + L

Lifecycle cost = $360 + (470kWh × 10years × 9cents/100) + ($11 × 10years)

=$893

7 0
4 years ago
A vector has an x component of -27.5 units and a y component of 41.4 units. Find the magnitude and direction of this vector. mag
evablogger [386]

Answer:

a.) magnitude __49.7__ unit(s)

b.) direction __123.6°_  counterclockwise from the +x axis

Explanation:

Let Vector is v

x-component of Vector v = x = -27.5 units   (minus sign indicate that x-component is along the minus x-axis )

y-component of Vector v = y = 41.4 units

Magnitude of v = ?

Direction of v = ?

To find the magnitude of the vector

                                     v =\sqrt{x^{2}+y^{2}  }  

                                     v = \sqrt{-27.5^{2}+41.4^{2} }

                                     v = 49.7 units  

To find direction

                                 θ = tan⁻¹(y/x)

                                 θ = tan⁻¹(41.4/-27.5)

                                 θ = -56.4°

This Angle is in the clockwise direction with respect to -x axis.

We need to find Angle counterclockwise from the +x axis.

So,

                                 θ = 180° - 56.4°

                                 θ = 123.6°                

The given vector is in 2nd quadrant

4 0
4 years ago
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