“How have formulas helped us understand compound structure and its behavior?”

1 answer:

3 0

Hello there!

Formulas have helped us understand the compound structure and its behavior by letting us know the exact composition of a molecule.

Different atoms have different properties, also, a different arrangement of atoms lead to different geometrical shapes. To understand compound structure and behavior it is necessary to know which atoms are in the molecule and how are they arranged. These two pieces of information can be obtained from the Chemical Formula, which tells us precisely the atoms and the proportions of each one in a given compound.

Have a nice day!

You might be interested in

A bike tire is inflated to a pressure of 984 kPa at 298 K. What is the temperature if the pressure decreases to 872 kPa?

navik [9.2K]

200 kPa. "Pressure." Macmillan Encyclopedia of Physics Reference. 530.03M. Volume 3. New York, New York.1996. pages 1235-1236. "Tire pressure are measured using a rather simple spring gauge, giving readings such as "29", meaning 29 psi." 200 kPa. Bernie, Jacques. Edmonton Bicycle Commuters

7 0

4 years ago

A chemist wants to find Kc for the following reaction at 751 K: 2NH3(g) + 3 I2 (g) LaTeX: \Longleftrightarrow ⟺ 6HI(g) + N2(g) K

charle [14.2K]

Answer: The equilibrium constant for the total reaction is $4.09\times 10^{-6}$

Explanation:

We are given:

$K_{c_1}=0.282\\\\K_{c_2}=41$

We are given two intermediate equations:

Equation 1: $N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g);K_{c_1}=0.282$

The expression of $K_{c_1}$ for the above equation is:

$K_{c_1}=\frac{[NH_3]^2}{[N_2][H_2]^3}$

$0.282=\frac{[NH_3]^2}{[N_2][H_2]^3}$ .......(1)

Equation 2: $H_2(g)+I_2(g)\rightleftharpoons 2HI(g);K_{c_2}=41$

The expression of $K_{c_2}$ for the above equation is:

$K_{c_2}=\frac{[HI]^2}{[H_2][I_2]}$

$41=\frac{[HI]^2}{[H_2][I_2]}$ ......(2)

Cubing both the sides of equation 2, because we need 3 moles of HI in the main expression if equilibrium constant.

$(41)^3=\frac{[HI]^6}{[H_2]^3[I_2]^3}$

Now, dividing expression 1 by expression 2, we get:

$\frac{K_{c_1}}{K_{c_2}}=\left(\frac{\frac{[NH_3]^2}{[N_2][H_2]^3}}{\frac{[HI]^6}{[H_2]^3[l_2]^3}}\right)\\\\\\\frac{0.282}{68921}=\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}$