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ZanzabumX [31]
3 years ago
9

What kind of ions do acids release when dissolved in water?

Chemistry
1 answer:
RSB [31]3 years ago
4 0
Virtually all acids release hydrogen ions (or protons) in the water
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Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Sh
Svet_ta [14]

Answer: The freezing point depression is 1.86^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=K_f\times m

\Delta T_f = Depression in freezing point

K_f = freezing point constant = 1.86^0C/m

m= molality = \frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m

\Delta T_f=1.86mol/kg^0C\times 1m  

\Delta T_f=1.86^0C  

Thus freezing point depression is 1.86^0C

3 0
3 years ago
Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a
Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: <em>3.465mg Fe / g sample. </em>As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = <em>86,6%</em>

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = <em>2.05mg Fe / g sample</em>

<em></em>

I hope it helps!

5 0
3 years ago
The most common form of energy encountered in chemical reactions is _____. Select one:
Svetllana [295]
The answer is b heat
3 0
3 years ago
Calculate the average weight of the dogs listed in the chart below.
pishuonlain [190]

Answer:

19

Explanation:

Once you add all the weights together, you end up with 114 then you divide it by how many dogs there are, 6. 114/6 = 19. The average is 19 lbs.

3 0
3 years ago
What happens when you add acetic acid vinegar and sodium bicarbonate baking soda nahco​
Sophie [7]

Explanation:

oh shi sorry I wish I could help but I'm stupid

8 0
3 years ago
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