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3 years ago

A 0.200 m wire is moved parallel to a 0.500 T

Physics

1 answer:

goldenfox [79]3 years ago

8 0

Answer:

The required emf moved across the wire is zero

Explanation:

For a moving charge particle, the magnetic force can be determined by using the formula;

$\varepsilon = Bvlsin \theta$

since the wire moves in parallel, the angle $\theta$ between magnetic field and velocity = 0°

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

∴

$\varepsilon = (0.500 \ T )(1.50 \ m/s) \times (0.200 \ m)\times sin (0)$

$\varepsilon = 0.15\times sin (0)$

$\varepsilon = 0$

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kkurt [141]

Answer:

Explanation:

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According to the conservation of energy, the total kinetic energy at the bottom is equal to the total potential energy at the top.

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3 years ago

Help with Order of Magnitude question?

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3 years ago

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jenyasd209 [6]

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I've attached the kinematic free body diagram.

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Where;

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m_p is the mass of the driver

m_v is the mass of the vehicle

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3 years ago

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dangina [55]

Answer:

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Explanation:

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3 years ago