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erastova [34]
3 years ago
10

A 0.200 m wire is moved parallel to a 0.500 T

Physics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

The required emf moved across the wire is zero

Explanation:

For a moving charge particle, the magnetic force can be determined by using the formula;

\varepsilon = Bvlsin \theta

since the wire moves in parallel, the angle \theta between magnetic field and velocity = 0°

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

∴

\varepsilon = (0.500  \ T )(1.50 \ m/s) \times (0.200 \ m)\times sin (0)

\varepsilon = 0.15\times sin (0)

\varepsilon = 0

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olga_2 [115]

Answer:

Spring's displacement, x = -0.04 meters.

Explanation:

Let the spring's displacement be x.

Given the following data;

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Number of shrews, n = 49

Spring constant, k = 24 N/m

We know that acceleration due to gravity, g is equal to 9.8 m/s².

To find the spring's displacement;

At equilibrium position:

Fnet = Felastic + Fg = 0

But, Felastic = -kx

Total mass, Mt = nm

Fg = -Mt = -nmg

-kx -nmg = 0

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kx = -nmg

Making x the subject of formula, we have;

x = \frac {-nmg}{k}

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x = \frac {-0.9604}{24}

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3 years ago
If sulfur 34 undergoes alpha decay, what will I become?
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