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Marina CMI [18]
3 years ago
6

How does the magnitude of the lever arm will change if you decrease the angle?

Physics
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer: It decreases.

Explanation:

Lever arm is defined as the <em>"perpendicular distance that exists from the rotation axis to the line of action of the force"</em>. Being its magnitude (Nm) related to the application of the force that produces a torque.  

To understand it better:  

The lever arm is an effective distance to apply a force with respect to a certain point, and this distance serves as an effective applied force amplification factor.

In this sense, Torque \tau is defined as:

\tau=rFsin \theta

Where:

r is the distance from the applied force to the fulcrum

F is the applied force

\theta is the angle between r and F

It is important to note, \tau is maximum when \theta=90\°. Then, assuming r and F remains the same, <u>if \theta decreases \tau decreases, as well.</u>

Hence:

If the angle \theta decreases, the magnitude of the lever arm will decrease.

So, the greater the lever arm, the greater the torque and the lesser the force we have to apply.

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