Answer:
0.7m/s^2
Explanation:
acceleration=(final-initial velocity)/time
x=(14-0)/20
x=14/20
x=0.7
On Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.
To find the answer, we have to know more about the Cassini-Huygens Mission.
<h3>
What is Cassini-Huygens mission?</h3>
- Before arriving at its final destination of Saturn in 2004 and beginning a series of flybys of Saturn's moons, the spacecraft contributed to studies of Jupiter for six months in 2000.
- In the same year, it launched the Huygens probe to explore Titan's atmosphere and surface makeup on Saturn's moon.
- During its second extended mission, Cassini sailed between the rings, entered the planet's atmosphere, and obtained the first measurements of a whole seasonal period for Saturn and its moons.
Thus, we can conclude that, on Titan, the largest moon of of Saturn did the Cassini-Huygens probe land in 2004.
Learn more about the Cassini-Huygens mission here:
brainly.com/question/27907891
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Answer: both environments are undergoing succession, but different kinds
Explanation:
C - because gravity is keeping them in orbit
So, the frequency of that light approximately 
<h3>Introduction</h3>
Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or
m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

With the following condition :
- c = the constant of the speed of light in a vacuum ≈
m/s
= wavelength (m)- f = electromagnetic wave frequency (Hz)
<h3>Problem Solving</h3>
We know that :
- c = the constant of the speed of light in a vacuum ≈
m/s
= wavelength =
m.
What was asked :
- f = electromagnetic wave frequency = ... Hz
Step by step :






<h3>Conclusion :</h3>
So, the frequency of that light approximately 
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