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3 years ago

Grade 11 physical science experiments on newtons second law experience

Physics

1 answer:

Nutka1998 [239]3 years ago

8 0

Answer:

Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass . Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing pushing on the pedals of your bicycle is the force.

Explanation:

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A 0.12 kg bird is flying at a constant speed of 7.8 m/s. what is the birds conetic energy?

lana [24]

KE=1/2mv^2 - equation for kinetic energy
KE=(1/2)(0.12 kg)((7.8 m/s)^2 - plug it into the formula
KE=(0.06 kg)(60.84 m/s) - multiply 1/2 to the mass and square the speed
KE= 3.7 J - answer
Hope this helps

7 0

3 years ago

Read 2 more answers

Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh

larisa [96]

Answer:

12.6332454263 m/s

Explanation:

m = Mass of car

v = Velocity of the car

$\mu$ = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

$\dfrac{mv^2}{r}=\mu mg\\\Rightarrow v=\sqrt{\mu gr}\\\Rightarrow v=\sqrt{0.638\times 9.81\times 25.5}\\\Rightarrow v=12.6332454263\ m/s$

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

4 0

3 years ago

Debris from the solar system strikes the Earth as which of the following

gogolik [260]

Answer: Meteors

Explanation:

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3 years ago

A car's fuel economy is 30 mpg. a warning light is displayed if the remaining distance that can be driven before the car runs ou

Alchen [17]

So 10 gallons of gas would let you travel 300 Miles.

x gallons = 50 Miles

10 : 300 :: x : 50

x = 500/300

x = 1.66667 gallons.

So, the car would run 10 - 1.6666 gallons = 8.33 gallons.

After that, the warning light turns ON!

Hope this helps!!

7 0

3 years ago

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Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass

Ilya [14]

Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

<em>Mass of the cart A = 0.4 kg</em>
<em>Mass of the cart B = 0.8 kg</em>

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

$m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s$

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

$F_A = -F_B$

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0

3 years ago

Grade 11 physical science experiments on newtons second law experience ​

Grade 11 physical science experiments on newtons second law experience