Answer:
- 75.5 g O₂ (g) can be produced from 42.6 g of H₂O (g)
Explanation:
<u>1) Balanced chemical equation (given):</u>
<u>2) Mole ratios:</u>
- 2 moles H₂O(g) : 2 moles H₂(g) : 2 moles O₂(g)
<u>3) Calculate the number of moles of reactant (H₂0):</u>
- number of moles = mass in grams / molar mass
- molar mass of water: 18.015 g/mol
- mass in grams of water: 42.6 g
- number of moles = 42.6 g / 18.05 g/mol = 2.36 moles H₂O
<u>4) Set a proportion using the mole ratio O₂ to H₂O and the actual number of moles of H₂O:</u>
- 2 moles O₂ / 2 moles H₂O = x / 2.36 moles H₂O
<u>5) Convert 2.36 moles O₂ to grams:</u>
- mass in grams = number of moles × molar mass
- mass = 2.36 moles × 32.00 g/mol = 75.5 g O₂
<span>The Mass Of The Products Of A Chemical Reaction Is equal to The Mass Of The Reactants.</span>
The reaction that would beat represent a typical reaction mechanism is when A and B react with each other to produce certain products.
C. The mass of an atom is greater than the combined masses of an atom's protons and electrons.
Existence of a neutron is predicted by Rutherford in 1920. So he explained difference between an atomic mass and an atomic number.
The density of sucrose is 1.58 g/ cm³
<em><u>Calculation</u></em>
Step 1 : calculate the volume of benzene
volume = mass/density
mass of benzene = total mass - mass of sucrose
=17.33 g - 9.35 g =7.98 g
volume = 7.98 / 0.879 =9.08 cm³
Step 2: calculate the volume of sucrose
volume of sucrose= Total volume - volume of benzene
Total volume = 15 ml =15 cm³
volume of sucrose is therefore = 15 cm³ - 9.08 cm³=5.92 cm³
Step 4: calculate the density of sucrose
density = mass/volume
= 9.35 g / 5.92 cm³ = 1.58 g/cm³
