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Arlecino [84]
4 years ago
8

The emission of a Beta particle has the effect of?

Physics
1 answer:
Zarrin [17]4 years ago
4 0

Answer: No change in mass

Explanation:

Beta-emission: In this process, a neutron gets converted into a proton and an electron. The electron is referred to as a beta-particle. The beta particle released carries a charge of -1 unit and has negligible mass.

General representation of an element is given as: _Z^A\textrm{X}

Z= Atomic number

A = mass number

X = chemical symbol of element

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

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if a mass on a spring bobs up nad down completing 2 full cycles every section. WHat are the periouds and frequency of the mass
Alika [10]

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the time taken to complete one full cycle.

Frequency (<em>f</em>) will be calculated first as

<em>f </em>= <em>N </em>÷<em> t</em>

where <em>N </em>is the number of cycles and <em>t </em>is the time taken to complete one full cycle. The unit for frequency is Hertz (Hz).

To calculate the period, <em>T, </em>the formula below will be used

<em>T </em>= 1 ÷ <em>f</em>

The unit for period is secs

4 0
3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t
elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

       Angular velocity (\omega) = 2.23 rps

     Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

             = 2.23 revolutions per second

             = 2.23 \times 2 \times 3.14 rad/s

             = 14.01 rad/s

Now, tangential speed will be calculated as follows.

  Tangential speed, v = R \times \omega

                               = 0.379 x 14.01

                               = 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0
3 years ago
How do I find work and time?
Arisa [49]
<span><span>Work from Days:<span><span><span>If A can do a piece of work in n days, then A's 1 day's work =</span></span></span></span><span /></span>\frac{1}{n}<span><span>Days from Work:<span><span>If A's 1 day's work =</span></span></span></span>\frac{1}{n}<span><span><span><span>,<span>then A can finish the work in n days</span></span></span></span><span>Ratio:If A is thrice as good a workman as B, then:Ratio of work done by A and B = 3 : 1.Ratio of times taken by A and B to finish a work = 1 : 3.</span></span>
3 0
3 years ago
Two cyclists, 50 miles apart, start riding toward each other at the same time. One cycles 4 times as fast as the other, and they
Bond [772]

Answer:speed of slower cyclist is 5 mph

Explanation:

Given

Distance between two cyclist is 50 miles

One cycle is 4 times fast as other

Speed of slower cyclist is r miles per hour

speed of faster cyclist is 4 r

they meet after t=2 hr

Distance traveled by fast cyclist is x=2\times 4r

Distance traveled by slower cyclist is y=2\times r

x+y=50

2\times 4r+2\times r=50

8r+2r=50

10r=50

r=5 mph

4 r=20 mph

speed of slower cyclist is 5 miles per hour

3 0
3 years ago
The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t
mel-nik [20]

Answer:

It will take 0.0611 sec for nerve signal to travel 1.1 m

Explanation:

We have given the nerve cell connecting the spinal card to feet is 1.1 m long

So length d = 1.1 m

And speed of the nerve impulse v = 18 m/sec

We have to find the time for nerve signal to travel that distance

Speed of the nerve signal is given by v=\frac{d}{t}

So t=\frac{d}{v}=\frac{1.1}{18}=0.0611sec

So it will take 0.0611 sec for nerve signal to travel 1.1 m

5 0
3 years ago
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