C because...
Models represent objects, events, and processes in the real world.
Models are often used when an object, event, or process
occurs too slowly or too quickly;
is too small or too large;
is too complicated or too dangerous.
The ocean is spreading at such a slow rate that it would take scientists 50 or more years to collect enough meaningful data from the ocean floor to complete a study. Therefore, scientists use models in order to both predict how the floor will keep spreading and to understand what the ocean floor looked like thousands of years in the past.
Answer:
390 J
Explanation:
m = 3 kg
u = 16 i + 2 j
(a) Magnitude of velocity =
= 16.1245 m/s
KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J
(b) v = 18 i + 14 j
Magnitude of velocity =
= 22.804 m/s
KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J
According to the work energy theorem
Work done = change in KE = KEf - KEi = 780 - 390 = 390 J
Answer: find the answer in the explanation
Explanation:
Average velocity is the average value of magnitude of initial velocity and final velocity.
If U = initial velocity and V = final velocity, then average velocity can be expressed as
Average velocity = ( U + V )/2
A vehicle who takes 60 minutes to cover 30 miles north and then 30 miles south and end up at the same place, has an average speed of 60 miles divided by 60 minutes, or 1 mile per minute.
Instantaneous velocity is the distance covered in a specific direction per time taken. Instantaneous velocity can be expressed as
Velocity = displacement/ time.
Uniform velocity occurs when we have a constant velocity. That is, when velocity does not change. When a vehicle travels in equal distances in equal intervals of time.
Answer:
a. v₁ = 16.2 m/s
b. μ = 0.251
Explanation:
Given:
θ = 15 ° , r = 100 m , v₂ = 15.0 km / h
a.
To determine v₁ to take a 100 m radius curve banked at 15 °
tan θ = v₁² / r * g
v₁ = √ r * g * tan θ
v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s
b.
To determine μ friction needed for a frightened
v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg
v₂ = 4.2 m/s
fk = μ * m * g
a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²
a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²
F₁ = m * a₁ , F₂ = m * a₂
fk = F₁ - F₂ ⇒ μ * m * g = m * ( a₁ - a₂)
μ * g = a₁ - a₂ ⇒ μ = a₁ - a₂ / g
μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)
μ = 0.251
Which two aspects of sound go together?
- <em>P</em><em>i</em><em>t</em><em>ch and frequency</em>
<u>Pitch</u><u> </u><u>and</u><u> </u><u>frequency</u><u> </u><u>are</u><u> </u><u>two</u><u> </u><u>aspects</u><u> </u><u>of</u><u> </u><u>sound</u><u> </u><u>that</u><u> </u><u>go</u><u> </u><u>together</u><u>.</u><u> </u><u>Pitch</u><u> </u><u>means</u><u> </u><u>Higness</u><u> </u><u>or</u><u> </u><u>Lowness</u><u> </u><u>of</u><u> </u><u>sound</u><u>.</u><u> </u><u>F</u><u>r</u><u>e</u><u>q</u><u>u</u><u>e</u><u>n</u><u>c</u><u>y</u><u> </u><u>is</u><u> </u><u>the measurement of the number of times that a repeated event occurs per unit of time.</u><u>.</u><u>.</u><u>~</u>