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3 years ago

The acidity of normal rain water is due to ______. a) SO2 b) CO2 c) NO2 d) NO

Chemistry

2 answers:

Viktor [21]3 years ago

6 0

The correct answer choice is CO₂ (B)

Rainwater naturally contains acids derived from carbon dioxide in the air and reacts with water vapor to form weak acids

H₂O + CO₂ ---> H₂CO₃

<h3><em>Further Explanation</em></h3>

Rainwater can cause damage to buildings, animals or plants due to acid rain

Acid rain occurs because other gases in the air mix with toxic gases to form acids

Rainwater naturally contains acids derived from carbon dioxide in the air and reacts with water vapor to form weak acids

H₂O + CO₂ ---> H₂CO₃

However, due to exhaust gases from industry, motor vehicles, or power plants that use fossil fuels containing sulfur to produce sulfur dioxide gas which will produce sulfuric acid

Sulfur combustion from fossil fuels

S + O₂ ----> SO₂

SO₂ produced from this exhaust gas reacts with O₂ oxygen which oxidizes SO₂ to SO₃

SO₂ + O₂ ----> SO₃

SO3 formed reacts with water vapor in the air to produce sulfuric acid as acid rain

SO₃ + H₂O ---> H₂SO₄

To reduce the pollution from this fossil fuel, various studies are now carried out as substitute energy that is more environmentally friendly such as solar energy and so on

<h3><em>Learn more </em></h3>

Acid rain is a secondary pollutant

brainly.com/question/1324440

The impact of from acid rain

brainly.com/question/8208861

Air pollution

brainly.com/question/1232950

Keywords: acid rain, air pollution, SO₃, H₂SO₄, fossil fuel

Gemiola [76]3 years ago

6 0

Answer:

SO₂

Explanation:

Acid rain is due to SO₂.

SO₂ + ½ O₂ + H2O = H₂SO₄

H₂SO₄= 2H⁺ + SO₄²⁻

Harmful pollutant in the air such as sulfur dioxide creates acid rain. SO₂ reacts with water vapor and oxygen to form sulfuric acid, which makes the rain acidic. H₂SO₄ releases H⁺ which decreases the pH of rain water. At acidic pH rainwater is harmful to both living beings and architectural objects.

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Suppose a species of snake is living in a certain area. Some of the snakes in the population are black and some are orange. Over

dybincka [34]

Answer:

The black snakes will survive and reproduce while the orange snakes die out.

Explanation:

The orange snakes will be easier to see by their prey and predators, and therefore will die out while the black snakes thrive because of their camouflage.

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3 years ago

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A 237g sample of molybdnum metal is heated to 100.1 0C and then dropped into an insulated cup containing 244 g of water at 10.0

miv72 [106K]

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

$Q_{metal} - Q_{water} = 0$

$Q_{metal} = Q_{water}$

Where:

$Q_{water}$ - Heat received by water, measured in joules.

$Q_{metal}$ - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

$m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})$

The specific heat of the metal is cleared within equation above:

$c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}$

If we know that $m_{water} = 0.237\,kg$ , $m_{metal} = 0.244\,kg$ , $c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}$ , $T_{w,o} = 10\,^{\circ}C$ , $T_{m,o} = 100.10\,^{\circ}C$ and $T = 15.30\,^{\circ}C$ , the specific heat of molybdenum is:

$c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}$

$c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}$

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

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3 years ago

Name the following ketone:

alekssr [168]

A. cyclohexyne is the answer

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3 years ago

Element m reacts with fluorine to form an ionic compound with the formula mf4. the m cation has 18 electrons. element m is:____.

polet [3.4K]

Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

<h3>What is Ionic Compound ?</h3>

An ionic compound is defined as the compound made up of ions that formed charge particles when an atom loses or gains electrons.

<h3>What is Cation ?</h3>

Cations are positively charged ions. It forms when an element lose one or more electrons.

The cation which has 18 electrons is Sn. Sn react with fluorine to form an ionic compound with the formula SnF₄ because Sn is large and F is very small in size.

Thus from the above conclusion we can say that Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

Learn more about the Ionic Compound here: brainly.com/question/2687188

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3 years ago

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