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pogonyaev
3 years ago
7

What are two ways that nonmetallic minerals can be used?

Chemistry
2 answers:
Veronika [31]3 years ago
8 0
Idk if i'm too late but the answer should be A.

Firdavs [7]3 years ago
6 0
I think the answer is A but not sure

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Un átomo neutro tiene número atómico 1 y número másico 3. Indica cuántos protones, neutrones y electrones tiene.
ahrayia [7]

Answer:

El átomo podes 1 protón, 1 electrón y 2 neutrones.

Explanation:

Cada elemento químico se caracteriza por el número de protones de su núcleo, que se denomina número atómico Z. Es decir, el número atómico​ de un elemento químico es el número total de protones que tiene cada átomo de ese elemento.

Los protones poseen carga positiva y se encuentran en el núcleo, en torno al cual se mueven otras partículas con carga eléctrica negativa que son los electrones. Así, el átomo es eléctricamente neutro, ya que la carga positiva de los protones está compensada por la carga negativa de los electrones.  Entonces, en todo átomo neutro el número de protones del núcleo es igual al de electrones de sus orbitales.

En este caso, un átomo neutro tiene número atómico 1. Entonces la cantidad de protones y electrones presentes en el átomo es 1.

En el núcleo de cada elemento, además de protones, también es posible encontrar neutrones, cuyo número puede variar. La masa atómica (A) se obtiene sumando el número de protones y de neutrones de un núcleo determinado:

Número másico (A) = número de protones + número de neutrones

En este caso, el átomo neutro posee 1 protón y su número másico es 3. Entonces:

3= 1 + número de neutrones

Resolviendo:

3 - 1= número de neutrones

2= número de neutrones

Entonces,<u><em> el átomo podes 1 protón, 1 electrón y 2 neutrones.</em></u>

6 0
3 years ago
During an experiment, the percent yield of calcium chloride from a reaction was 85.22%. Theoretically, the expected amount shoul
devlian [24]

The formula to find yield is

(Actual Yield)/(Theorectical Yield) x100

Just do the math.

85.22% x 113 = 96.2986

Convert it to 3 significant figures

Ans: 96.3g

7 0
3 years ago
Read 2 more answers
The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti
gulaghasi [49]

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

6 0
3 years ago
Read 2 more answers
What is the part of the experiment that is measured? * 2 points control group constant independent variable dependent variable?
Arturiano [62]
The dependent variable is what is being tested. independent is what forces or effects the dependent
4 0
3 years ago
On a hot summer day you and some friends decide you want to cool down your pool. Determine the mass of ice you would need to add
sergeinik [125]

Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is 16.14 \times 10^{4} kg.

Explanation:

We know that relation between heat energy and specific heat is as follows.

                 q = m \times S \times \Delta T

As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.

          Mass of water = Volume × Density

                                  = 400,000 L \times 1 kg/L

                                  = 400,000 kg

or,                              = 400,000 \times 10^{3} g    (as 1 kg = 1000 g)

Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.

         \Delta T = 305 K - 273 K

                    = 32 K

Now, putting the given values into the above formula and calculate the heat energy as follows.

            q = m \times S \times \Delta T

                = 400,000 \times 10^{3} \times 4.2 \times 32 K

                = 5376 \times 10^{7} J

or,            = 5376 \times 10^{4} kJ

According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of 5376 \times 10^{4} kJ  is calculated as follows.

            Mass = \frac{5376 \times 10^{4} kJ}{333 kJ/Kg} \times 1 kg

                      = 16.14 \times 10^{4} kg

Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is 16.14 \times 10^{4} kg.

3 0
3 years ago
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