Answer: ![\dfrac{7}{132}](https://tex.z-dn.net/?f=%5Cdfrac%7B7%7D%7B132%7D)
Step-by-step explanation:
Total marbles in the jar = 8+25 = 33
Using combinations, the number of ways of choosing two marbles out of 33=
(total outcomes)
Similarly, the number of ways of choosing two red marbles =
(favorable outcomes)
Required probability = ![\dfrac{\text{favorable outcomes}}{\text{total outcomes}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7Bfavorable%20outcomes%7D%7D%7B%5Ctext%7Btotal%20outcomes%7D%7D)
![=\dfrac{28}{528}\\\\=\dfrac{7}{132}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B28%7D%7B528%7D%5C%5C%5C%5C%3D%5Cdfrac%7B7%7D%7B132%7D)
hence, required probability = ![\dfrac{7}{132}](https://tex.z-dn.net/?f=%5Cdfrac%7B7%7D%7B132%7D)
Answer:
<h2>Jake's strand represents 4 times David's strand.</h2>
Step-by-step explanation:
To find the ratio between these diameters, we just need to divide them
and ![d=0.0012cm](https://tex.z-dn.net/?f=d%3D0.0012cm)
If we divide
![\frac{k}{d}=\frac{0.005}{0.0012} \approx 4](https://tex.z-dn.net/?f=%5Cfrac%7Bk%7D%7Bd%7D%3D%5Cfrac%7B0.005%7D%7B0.0012%7D%20%5Capprox%204)
Therefore, Jake's strand represents 4 times David's strand.
Answer:
yeah i dont know i want my points xd 494 4944
Step-by-step explanation:
Answer:
Option C. P = 3/q
Step-by-step explanation:
To know the the correct answer to the question, do the following:
Let us assume a certain number for P say 2 and 3, and then, find the corresponding value for q in each case to see which will give a decreased value for q.
Option A
When P = 2, q =.?
P = 3q
2 = 3q
Divide both side by 3
q = 2/3
When P = 3, q =.?
P = 3q
3 = 3q
Divide both side 3
q = 3/3
q = 1
From the above illustration, we can see that as P increase, q also increase.
Option B
When P = 2, q =.?
P – 3 = q
2 – 3 = q
q = – 1
When P = 3, q =.?
P – 3 = q
3 – 3 = q
q = 0
From the above illustration, we can see that as P increase, q also increase.
Option C
When P = 2, q =.?
P = 3/q
2 = 3/q
Cross multiply
2 × q = 3
Divide both side by 2
q = 3/2
q = 1.5
When P = 3, q =.?
P = 3/q
3 = 3/q
Cross multiply
3 × q = 3
Divide both side by 3
q = 3/3
q = 1
From the above illustration, we can see that as P increase, q decreases.
Option D.
When P = 2, q =.?
1/p = 3/q
1/2 = 3/q
Cross multiply
1 × q = 2 × 3
q = 6
When P = 3, q =.?
1/p = 3/q
1/3 = 3/q
Cross multiply
1 × q = 3 × 3
q = 9
From the above illustration, we can see that as P increase, q also increase.
Now, haven done the above, only option C gives a decreased value for q as the value of P increases.