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tatyana61 [14]
3 years ago
11

In a series circuit,

Physics
1 answer:
expeople1 [14]3 years ago
4 0
A) Electrons in a series circuit travel in one path, and if the path or wire is broken, the current has no other path to travel, and the circuit does not work. Hope this helps!
You might be interested in
Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20°C. Container A is rigid. Container B has a 100 cm^2 pis
Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial  pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

1)

Final Temperature of the gas in A will b GREATER than the temperature in B

2)

Diagram of both processes on a single PV has been uploaded below,

3)

Initial  pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) /  0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial  pressures in containers A and B is 3039.87 J/liters

4)

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

Also work done = P( V₂ - V₁ )

so we substitute

375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

7 0
3 years ago
A jet airliner moving initially at 612 mph (with respect to the ground) to the east moves into a region where the wind is blowin
Ganezh [65]

Answer:

966.22 mph

Explanation:

Velocity of plane with respect to wind (Vp,w)= 612 mph east

velocity of wind with respect to ground, (Vw,g) = 362 mph at 15° North of

east

Write the velocities in vector form

V_{p,w}=612\widehat{i}

V_{w,g}=362\left ( Cos15\widehat{i}+Sin15\widehat{j} \right )= 349.67\widehat{i}+93.69\widehat{j}

Use the formula for the relative velocity

V_{p,w}=V_{p,g}-V_{w,g}

Where, V(p,w) is the velocity of plane with respect to wind

V(p,g) is the velocity of plane with respect to ground

V(w,g) is the velocity of wind with respect to ground

So, V_{p,g}=V_{p,w}+V_{w,g}

V_{p,g}=\left ( 612+349.67 \right )\widehat{i}+93.69\widehat{j}

V_{p,g}=961.67\widehat{i}+93.69\widehat{j}

Magnitude of velocity of lane with respect to ground

V_{p,g} = \sqrt{961.67^{2}+93.69^{2}}

V(p,g) = 966.22 mph

5 0
4 years ago
If a star has no measurable parallax, what can you infer?
AnnZ [28]
The star is FARTHER from Earth than the limit of our ability to measure parallax.

The NEAREST star outside the solar system has a parallax angle of 0.742 SECOND. That's like 0.000206 of a degree ! ALL other stars have SMALLER parallax.

I have no idea how they measure angles like these ... especially when the change in direction takes six months to happen !
5 0
4 years ago
Read 2 more answers
A conductor bent into a semicircle of total length 3.88 m is placed in a 2.0 T magnetic field perpendicular to the plane of the
ivolga24 [154]

Answer:

Magnetic force, F = 38.95 N

Explanation:

Given that,

Length of the conductor, L = 3.88 m

Magnetic field, B = 2 T

Current flowing in the conductor, I = 5.02 A

The magnetic field perpendicular to the plane of the semicircle. The angle between the magnetic field and the plane is 90 degrees. The expression for the magnetic force is given by:

F=ILB\ sin\theta

F=ILB

F=5.02\times 3.88\times 2

F = 38.95 N

So, the magnitude of the total force acting on the conductor in the magnetic field is 38.95 N. Hence, this is the required solution.

5 0
4 years ago
(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
attashe74 [19]

Complete Question

(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?

(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?

The  tensile  strength of the nylon string is  600*10^{6} \  N/m^2

Answer:

A

   T = 471.3 \  N

B

 To prevent breakage the thickness of the string is increased

  String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Explanation:

From the question we are told that

     The  diameter is  d =  1.00 \ mm  =  0.001 \  m  

       The  tensile strength of the nylon string is \sigma =  600 *10^{6} \  N/m^2

  Generally the radius is mathematically evaluated as

     r=  \frac{d}{2}

=>    r =  \frac{0.001}{2}

=>     r =  0.0005 \  m

The cross sectional area is mathematically represented as

     A = \pi  r^2

=>   A =  3.142  *  (0.005)^2

=>    A =  7.855*10^{-7}\  m^2

Generally the tensile strength of nylon is mathematically represented as

      \sigma  = \frac{T}{ A }

Where T is the tension on the maximum tension on the string

 So  

           T =  \sigma  *  A

=>          T =  600*10^{6} *  7.855*10^{-7}

=>         T = 471.3 \  N

Form the equation above  we  see that

        T  \  \alpha \  A

So if the tension is  increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional  area )

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

8 0
4 years ago
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