All categories

3 years ago

What is a disadvantage of constructing hydroelectric dams as a source of

Physics

1 answer:

Papessa [141]3 years ago

8 0

Answer:

I think maybe C. They require a large amount of land disturbance and potential displacement of people

Explanation:

Hope this helps.

You might be interested in

A substance has a boiling point of 220 degrees Celsius and a melting point of −120 degrees Celsius. What state will it be at roo

ozzi

Room temperature is 36 degrees celsius

7 0

3 years ago

A combination of two or more simple machines is a (n)

Lilit [14]

A compound Machine is 2 machines that work together in order to make a task easier.

8 0

3 years ago

The mass of a hot air ballon including its cargo is 320 kg. the hot air inside it has a density of 1.19 kg/m^3. the density of t

ASHA 777 [7]

Answer:

40454.4 N

Explanation:

mass, m = 320 kg

density of hot air, d = 1.19 kg/m^3

density of cold air, d' = 1.29 kg/m^3

Volume of the balloon, V = mass / density

V = 320 / (1.29 - 1.19)

V = 3200 m^3

So, buoyant force

F = Volume x density outside x gravity

F = 3200 x 1.29 x 9.8

F = 40454.4 N

thus, the buoyant force is 40454.4 N.

3 0

4 years ago

The tub of a washer goes into its spin-dry cy-cle, starting from rest and reaching an angularspeed of 3.1 rev/s in 10.7 s.At thi

neonofarm [45]

Answer:

35 revolutions

Explanation:

t = Time taken

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

$\alpha$ = Angular acceleration

$\theta$ = Number of rotation

Equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3-0}{10.7}\\\Rightarrow \alpha=0.28037\ rev/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{3.1^2-0^2}{2\times 0.28037}\\\Rightarrow \theta=17.13806\ rev$

Number of revolutions in the 10.7 seconds is 17.13806

$\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3.1}{11.2}\\\Rightarrow a=-0.27678\ rev/s^2$

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3.1^2}{2\times -0.27678}\\\Rightarrow \theta=17.36035\ rev$

Number of revolutions in the 11.2 seconds is 17.36035

Total total number of revolutions in the 21.9 second interval is 17.13806+17.36035 = 34.49841 = 35 revolutions

3 0

4 years ago

Kepler's _____ of planetary motion station states that the planets have an elliptical orbit, with the sun at one focal point the

maw [93]

C. 2nd law I think hope its right

3 0

4 years ago

Read 2 more answers