Answer:
A. harmful substances in the air, water, or soil
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Answer:
A) The wave equation is given as

According to the above equation, k = 0.004 and ω = 5.05.
Using the following identities, we can find the period of the wave.

T = 1.25 s.
For the horizontal distance travelled by one period of time, x = λ.


B) The wave number, k = 0.004 . The number of waves per second is the frequency, so f = 0.8.
C) The propagation speed of the wave is
The velocity of the wave is the derivative of the position function.

The maximum velocity is when the derivative of the velocity function is equal to zero.

In order this to be zero, cosine term must be equal to zero.

The reason that cosine term is set to be 5π/2 is that time cannot be zero. For π/2 and 3π/2, t<0.

The vertical movement of the projectile is described by:
y = H - gt² / 2
When the cannonball is on the ground, y= 0 so:
0 = H - gt² /2
Solving for t:

The horizontally movement of the projectile is described by:
x = v₀t
Solving for v₀:
v₀ = x/t
v₀ = 175 m / 2.8 s
v₀ = 61.5 m/s
Answer:
The frequency of vibration will be unchanged.
Explanation:
The frequency of oscillation of a simple pendulum is given by

where,
is the acceleration due to gravity and
is the length of the pendulum.
It can be seen from the formula that the frequency of the pendulum is independent of the mass.
Thus, the frequency of vibration will be same.
A change that would most improve his results would be; D) Connecting the galvanometer to the coil