Answer:
Density of 127 I = 
Also, 
Explanation:
Given, the radius of a nucleus is given as
.
where,
- A is the mass number of the nucleus.
The density of the nucleus is defined as the mass of the nucleus M per unit volume V.
For the nucleus 127 I,
Mass, M = 
Mass number, A = 127.
Therefore, the density of the 127 I nucleus is given by
On comparing with the density of the solid iodine,
If you increase the mass of an object and want to move an object a specific distance, then you need to do extra work than the earlier
<h3>What is work done?</h3>
The total amount of energy transferred when a force is applied to move an object through some distance
Work Done = Force * Displacement
For example, let us suppose a force of 10 N is used to displace an object by a displacement of 5 m then the work done on the object can be calculated by the above-mentioned formula
work done = 10 N ×5 m
=50 N m
Thus, when an object's mass is increased and it is desired to move it a certain distance, more work must be done than previously.
Learn more about work done from here
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Answer:
r = 1.45 Å
Explanation:
given,
λ = 1.436 Å
θ = 20.62°
d = a
n = 2
metal gold crystallizes in a face centered cubic unit cell
Radius of the gold atom = ?
using Bragg's Law
n λ = 2 d sin θ
2 x 1.436 Å = 2 a sin 20.62°
a = 4.077 Å
We know relation of radius for face centered cubic unit cell
r = 1.45 Å
the radius of a(n) gold atom. is equal to 1.45 Å
They hit each other.This is the 3rd law I think
