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butalik [34]
3 years ago
10

Chemical substances in food that have specific functions in your body are called?

Physics
1 answer:
andreev551 [17]3 years ago
4 0

Answer:

Chemical substances in food that have specific functions in your body are called Nutrients. Examples: proteins, fats, carbohydrates, vitamins, and minerals

Explanation:

These chemical substances keep our body healthy.

These chemical substances prevent the premature aging.

They help our body to fight against diseases.

They build the new tissues and cells for growth.

And in short, they help in the growth, development of our body.

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Answer:

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Arunner starts from rest and accelerates uniformly to a speed of 8.0 meters per
VladimirAG [237]

Answer:

2.0 m/s/s

Explanation:

The acceleration of an object is the rate of change of velocity of the object.

Mathematically, it is given by:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

Acceleration is a vector, so it has both a magnitude and a direction.

For the runner in this problem, we have:

u = 0 is the initial velocity (he starts from rest)

v = 8.0 m/s is the final velocity

t = 4.0 s is the time taken

Substituting, we find

a=\frac{8.0-0}{4.0}=2.0 m/s^2

3 0
3 years ago
1.)Which is the correctly balanced equation?
iVinArrow [24]
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       C. Cl2 + 2NaI --> 2NaCl + I2


B. In the given chemical reaction above, heat is emitted such that it appears in the product side of the equation. Hence, this is an example of a combustion reaction. 

C. Similar with the reasoning in letter A, the answer to this item is,
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8 0
3 years ago
You are traveling on an interstate highway at the posted speed limit of 70 mph when you see that the traffic in front of you has
vovikov84 [41]

Answer:8.75 s,

136.89 m

Explanation:

Given

Initial velocity=70 mph\approx 31.29 m/s

velocity after 5 s is 30 mph\approx 13.41 m/s

Therefore acceleration during these 5 s

a=\frac{v-u}{t}

a=\frac{13.41-31.29}{5}=-3.576 m/s^2

therefore time required to stop

v=u+at

here v=final velocity =0 m/s

initial velocity =31.29 m/s

0=31.29-3.576\times t

t=\frac{31.29}{3.576}=8.75 s

(b)total distance traveled before stoppage

v^2-u^2=2as

0^2-31.29^2=2\times (-3.576)\cdot s

s=136.89 m

3 0
3 years ago
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