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2 years ago

6. The electric field caused by an electron is weakest near the electron.

Physics

1 answer:

OLga [1]2 years ago

5 0

6. "The electric field caused by an electron is weakest near the electron" is FALSE.

7. "An electric field becomes weaker as distance from the electron increase" is TRUE.

<u>Explanation:</u>

The "electrical field" covers the electrical charge and exerts, attracts or repels other charges in the field.The electric field caused by an electron is strongest near the electron while it become weak as distance from the electron increase.

The reason behind is, at a point the direction of the field line is at that point the direction of the field. The relative magnitude of the electric field will be proportional to the field line density. The field is strongest where the field lines are near together and when the field lines are at increasing distance the field is weakest.

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ou purchase a rectangular piece of metal that has dimen- sions 5.0 * 15.0 * 30.0 mm and mass 0.0158 kg. The seller tells you tha

Natalija [7]

Answer: 7022.2kg/m³, yes, I was cheated

Explanation:

Density of an object is defined as the ratio of the mass of the object to its volume. Mathematically;

Density = Mass/Volume

Note that the unit of both mass and volume must be standard unit.

Given mass = 0.0158kg

Dimension of the metal = 5mm×15mm×30mm

Note that 1mm = 0.001m

The volume of the metal will be

0.005×0.015×0.03

= 0.00000225m³

Density = 0.0158/0.00000225

Average density of the metal = 7022.2kg/m³

Since the standard density of Gold is 19,320kg/m³ and is higher than the density prescribed for me, it shows the I was cheated.

4 0

3 years ago

A 120-kg object and a 420-kg object are separated by 3.00 m At what position (other than an infinitely remote one) can the 51.0-

djverab [1.8K]

Answer:

1.045 m from 120 kg

Explanation:

m1 = 120 kg

m2 = 420 kg

m = 51 kg

d = 3 m

Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.

By use of the gravitational force

Force on m due to m1 is equal to the force on m due to m2.

$\frac{Gm_{1}m}{y^{2}}=\frac{Gm_{2}m}{\left ( d-y \right )^{2}}$

$\frac{m_{1}}{y^{2}}=\frac{m_{2}}{\left ( d-y \right )^{2}}$

$\frac{3-y}{y}=\sqrt{\frac{7}{2}}$

3 - y = 1.87 y

3 = 2.87 y

y = 1.045 m

Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.

6 0

3 years ago

Calculate Vector component in Y if the hypotenuse is 32 and angle is 45

Lerok [7]

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

$v_y = v \times sin(\theta)$

Substituting the values from the question gives;

$v_y = 32 \times sin(45^{\circ}) \approx 22.6$

The vector component in the y-axis, $v_y$ , is approximately 22.6.

8 0

2 years ago

Is silver magnetic or not ?

evablogger [386]

Answer:

Yes, but its magnetic power is very weak so its not that noticeable to the average person whos not paying attention.

4 0

2 years ago

the deepest point in the sea is 100m below sea level .what arr the water pressure at this depth and the total pressure due to wa

fomenos

The water pressure at this depth and the total pressure due to water and atmosphere are 10.3 x 10⁵ Pa and 11.31× 10⁵ Pa.

<h3>What is pressure?</h3>

The pressure is the amount of force applied per unit area.

Atmospheric pressure, Patm =1.01×10⁵ Pa

Density of water, ρ=1030 kg/m³

Depth, h=100 m

Pressure =ρgh

P = 1030×10×100

P = 10.3 x 10⁵ Pa.

Total pressure, P=Po +ρgh

P=1.01×10⁵ + 1030×10×100

P=11.31× 10⁵ Pa

Hence, total pressure is 11.31× 10⁵ Pa.

Learn more about pressure.

brainly.com/question/12971272

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4 0

1 year ago