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MA_775_DIABLO [31]

3 years ago

6

A space traveller weighs herself on earth, at a location where the acceleration due to gravity is 9.82 m/s2, and finds a value o

f 585 n. what is her mass?

1 answer:

rewona [7]3 years ago

6 0

59.57kg is the answer

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A constant amount of charge passes through a conductor. How is current affected if the same amount of charge passes in less time

baherus [9]

Answer:

B. The current increases.

Explanation:

As we know that rate of flow of charge through the conductor is known as electric current

So we have

$i = \frac{q}{t}$

here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased

so we can say that the ratio of charge and time will increase

so here we have

$i = increased$

So correct answer will be

B. The current increases.

4 0

4 years ago

(a) Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. a(t)

dolphi86 [110]

Answer:

$r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k$

Explanation:

a(t)=20t i+sin(t) j +cos(2t) k

v(t)= $\int\limits^a_b {a(t)} \, dt$

= $(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k$ ---------------eqn 1

given v(0)=i

i= $c_1i+(-1+c_2)j+(0+c_3)k$

$c_1=1$ $c_2=1$ $c_3=0$

from equation 1

V(t)= $(10t^2+c_1)i+(-cost+c_2)j+\frac{sin2t}{2}k$ ----------eqn 2

now r(t)= $\int\limits^a_b {v (t)} \, dt$

$(\frac{10t^3}{3}+t+c_1)i+(-sint+t+c_2)j+(\frac{-cos2t}{4}+c_3)k$

given r(0)=j

0i+1j+ok = $c_1i+c_2j+(\frac{-1}{4}+c_3)k$

$c_1=0$ $c_2=0$ $c_3 = \frac{1}{4}$

$r(t)=(\frac{10t^3}{3}+t)i+(-sint+t+1)j+(\frac{-cos2t}{4}+\frac{1}{4})k$

8 0

3 years ago

Please help fast!! I need this in less than 17 hours!

djyliett [7]

SOLUTION is given in attachment below.

7 0

3 years ago

What is the relationship between the frequency of light and its color?

shtirl [24]

Answer:

we understand it by electromagnetic spectrum. and we velength is the distance between identical location on adjecent waves ( see figure below)

3 0

3 years ago

How much energy is created when there is 110 W of<br> power over 30s?

Makovka662 [10]

Answer:

3300 J

Explanation:
P = Q/t

Q = Pt = 110 * 30 = 3300 J

5 0

2 years ago