Answer:
I think the answer is C.) -3.2 > -4.1
Answer:
You will need 3 6/13 quarts of peanuts to make 3 jars of peanuts butter
Step-by-step explanation:
To make this answering seamless, we make the mixed fractions into improper fractions
Hence 2 1/2 becomes 5/2
while 2 1/6 becomes 13/6
Here we are told that a bag with 5/2 quarts of peanuts can make 13/6 jars of peanuts butter
Hence, x quarts of peanuts will make 3 jars of peanuts butter
To get the value of x, what we simply need to do is to cross multiply.
Thus, we have
5/2 - 13/6
x - 3
3 * 5/2 = 13/6 * x
15/2 = 13x/6
26x = 90
x = 90/26
x = 45/13
x = 3 6/13
Answer:
Part A: 64 (right-side 3th cell) and 7 (left-side 4th cell)
Part B: 5 hours- $45; 6 hours- $54; 8 hours- $72
Part C: $5 more
Step-by-step explanation:
Explanation for Part C- We know that if she works 5 hours mowing lawns, she will earn $40. But, when she works at the theme park we use the ratio given to find out how much she earn per hour. In her case she earns $9 for every hour she works at the theme park. now if you multiply that by 5 we can find out how much she earns in 5 hours which is $45. This is $5 more than what she earns mowing lawns for the same amount of time. Here we can conclude that Barbara earns $5 dollars more working at the theme park for 5 hours rather that mowing lawns.
If you can please name me the brainliest that would be much appreciated. Thanks and Good Luck!
The answer is C
Is shows a change of rate for the integer
Hope this helps
Answer:
a = length of the base = 2.172 m
b = width of the base = 1.357 m
c = height = 4.072 m
Step-by-step explanation:
Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?
lets call a = length of the base
b = width of the base
c = height
V = a.b.c = 12
Area without the top:
Area = ab + 2bc + 2ac
Cost = 12ab + 8.2bc + 8.2ac
Cost = 12ab + 16bc + 16ac
height = 3.width
c = 3b
Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab
abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²
Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b
C(b) = 48b² + 240/b
C'(b) = 96b - 240/b²
Minimum cost: C'(b) = 0
96b - 240/b² = 0
(96b³ - 240)/b² = 0
96b³ - 240 = 0
96b³ = 240
b³ = 240/96
b³ = 2.5
b = 1.357m
c = 3b = 3*1.357 = 4.072m
a = 4/b² = 2.172m
