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Tpy6a [65]
3 years ago
9

A student designed an experiment to test the effect on the magnitude of the magnetic field that is generated around the wire loo

p. The student increased the current that passes through the wire and tests the magnitude of the magnetic force that is generated. The experimental setup is shown here. Which statements accurately describe this experimental design? Select ALL that apply. A) The student's dependent variable is the size of the wire loop. B) The student's independent variable is the size of the wire loop. C) The student's dependent variable is the magnitude of the magnetic field that is generated. D) The student's independent variable is the magnitude of the magnetic field that is generated. E) The student's independent variable is the amount of current that is being passed through the wire.
Chemistry
1 answer:
kykrilka [37]3 years ago
5 0

Answer: C ) the student’s dependent variable is the magnitude of the magnetic field that is generated

E ) the student’s independent variable is the amount of current that is being passed through the wire

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A gas occupies the volume of 215ml at 15C and 86.4kPa?
kherson [118]

Answer:

About 0.1738 liters

Explanation:

Using the formula PV=nRT, where p represents pressure in atmospheres, v represents volume in liters, n represents the number of moles of ideal gas, R represents the ideal gas constant, and T represents the temperature in kelvin, you can solve this problem. But first, you need to convert to the proper units. 215ml=0.215L, 86.4kPa is about 0.8527 atmospheres, and 15C is 288K. Plugging this into the equation, you get:

0.8527\cdot 0.215=n \cdot 0.0821 \cdot 288\\n\approx 7.754 \cdot 10^{-3}

Now that you know the number of moles of gas, you can plug back into the equation with STP conditions:

1V=7.754 \cdot 10^{-3} \cdot 0.0821 \cdot 273\\V\approx 0.1738L

Hope this helps!

3 0
4 years ago
Which choice lists the correct order of the coefficients of each substance in the following neutralization reaction when the equ
Gnoma [55]
The third one you have listed 


4 0
3 years ago
How do you define medium and high level profession?according to class 8?
abruzzese [7]

Answer:

Answer: medium level profession can be defined as some one who has moved past entry level but isn't nearing the end . whereas high level profession means a person has moved past entry level and also has reached the end.

3 0
3 years ago
Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
RideAnS [48]

Answer: D=8.27 g/cm³

Explanation:

Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.

D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}

With this equation, the m³ and kg cancel out, and we are left with g/cm³.

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3 0
3 years ago
A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
3 years ago
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