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ser-zykov [4K]
3 years ago
11

Please please help 100 points

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0

We're given

\displaystyle \int_4^{-10} g(x) \, dx = -3

which immediately tells us that

\displaystyle \int_{-10}^4 g(x) \, dx = 3

In other words, swapping the limits of the integral negates its value.

Also,

\displaystyle \int_4^6 g(x) \, dx = 5

The integral we want to compute is

\displaystyle \int_{-10}^6 g(x) \, dx

which we can do by splitting up the integral at x = 4 and using the known values above. Then the integral we want is

\displaystyle \int_{-10}^6 g(x) \, dx = \int_{-10}^4 g(x) \, dx + \int_4^6 g(x) \, dx = 3 + 5 = \boxed{8}

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