Answer:
300.16m/s
Explanation:
An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?
note velocity is the change in displacement to time
to find the magnitude of the initial speed ,
we will find the square of the vertical component plus the square of the horizontal component. then we look for the square root
U=
U=
U=90,100^2
U=300.16m/s
means that it covers 300.16m in 1 seconds
Answer:
Acceleration is 7.990487515m/s²
Initial velocity is 0m.s
Explanation:
s=ut+(1/2)at²
210=0(7.25)+(1/2)a(7.25²)
210=26.28125a
∴a=7.990487515m/s²
'Vi' or 'u' is the inital speed. Since it starts from rest, this equals 0.
Half life is 5700 years,that is 50%.
6.25% means 1/16 of the life is left.
T^1/16 =T^1/2*4.
5700 × 4 =22800 years
The answer given by E2020 is
"The padding around the goal post increases the time of the collision between the player and the post, which decreases the force exerted to bring the player to a stop"