It contains no large maria
From an energy balance, we can use this formula to solve for the angular speed of the chimney
ω^2 = 3g / h sin θ
Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s
The formula for radial acceleration is:
a = rω^2
So,
a = 53.2 (0.987) = 52.494 /s^2
The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887
The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2
If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
Solving for θ
θ = 67°
Answer:
Explanation:
We have,
The surface temperature of the star is 60,000 K
It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :
Here,
= wavelength
So, the wavelength of the star is 
.
Explanation:
PE = mgz = 200 * 9.81 *1000 = 1962 KJ
Yes it can, because −3.5 lies to the left of −0.5.
Yes it can, because −3.5 lies to the right of −0.5.
No it cannot, because −3.5 lies to the left of −0.5.
No it cannot, because −3.5 lies to the right of −0.5.
Yes it can, because −3.5 lies to the left of −0.5.
Answer: Option A.
<u>Explanation:</u>
This option has been chosen because the left of the 0 has been shaded and all the negative values lies on the left of zero. So -3.5 lies to the left of -0.5 and is in the shaded region of the number line.
In a number line, the figure -3.5 lies on the left side compared to the number -0.5 because the higher the value on the negative side of the number line, more left it would be on the number line.
