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Sladkaya [172]
3 years ago
10

Which protects a cell and forms it’s boundary

Physics
1 answer:
ivann1987 [24]3 years ago
5 0

Answer:

For a plant cell: The cell wall and the cell membrane

For animal cells: Just the cell membrane

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Which of these statements about neutrons is true? . . . A.. Neutrons travel around the nucleus of an atom.. . . B.. A neutron ha
Bas_tet [7]
<span>B is the correct answer. Neutrons have no charge. In contrast, protons are positively charged and electrons have negative charge. These charges are all relative to each other. The protons and neutrons can be found inside the atom of an element. Electrons float around the outside.</span>
8 0
3 years ago
Read 2 more answers
1. What is work done in holding a 15kg suitcase while waiting for a bus for 15 minutes?
Anettt [7]
The man is holding the suitcase at the same height above the surface of earth. So the gravitation potential energy remains the same. 

<span>work done is force * displacement = weight * 0 = 0</span>
7 0
3 years ago
a 200 kg crate is pushed horizontally with a force of 700 N. If the coefficient of friction is 0.2 calculate the acceleration of
Crazy boy [7]

Answer:

a=1.54\ m/s^2

Explanation:

<u>Net Force</u>

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

\displaystyle a=\frac{F_n}{m}

Where

Fn = Net force

m  = mass

The m=200 kg crate is pushed horizontally with a force Fa=700 N. The friction force opposes motion and a horizontal net force appears causing the acceleration.

The forces on the vertical direction are in balance since the crate does not accelerate in that direction, thus the weight and the normal force are equal:

N = W = mg

The friction force can be calculated by using the coefficient of friction μ:

F_r=\mu N

Calculating the normal force:

N = 200 * 9.8 = 1,960 N

The friction force is:

F_r=0.2*1,960

F_r=392\ N

The horizontal net force is:

F_n = F_a-F_r=700\ N - 392\ N

F_n = 308\ N

Finally, the acceleration is computed:

\displaystyle a=\frac{308}{200}

\boxed{a=1.54\ m/s^2}

3 0
3 years ago
What is the frequency of a wave having a period equal to 18 seconds? a. 6.6 × 10-2 hertz b. 5.5 × 10-2 hertz c. 3.3 × 10-2 hertz
irakobra [83]
Frequency = 1/period. ... 1 / 18 sec = (1/18) per sec. That's 0.056 per sec or 0.056 Hz. (rounded) (5.6 x 10^-2 Hz)
6 0
3 years ago
Read 2 more answers
A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc
marin [14]

Answer:

Time period of the osculation will be 0.0671 sec  

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So kx=mg

k\times 0.04=0.012\times 9.8

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

T=2\pi \sqrt{\frac{m}{k}}

=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec

4 0
3 years ago
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