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7nadin3 [17]
3 years ago
15

A student connects an object with mass m to a rope with a length r and then rotates the rope around her head parallel to the gro

und. the object takes 0.5 seconds to complete one rotation.
mass= 50 kg. length of the rope = 1.2 m
what is the objects speed of rotation?
what is the objects centripetal acceleration?
what tension force is required to maintain this motion?​
Physics
1 answer:
Alexandra [31]3 years ago
7 0

The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.

Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2<em>π</em> (1.2 m) = 2.4<em>π</em> m ≈ 7.5 m, so that

2 rot/s = (2 rot/s) • (2.4<em>π</em> m/rot) = 4.8<em>π</em> m/s ≈ 15 m/s

thus giving it a centripetal acceleration of

<em>a</em> = (4.8<em>π</em> m/s)² / (1.2 m) ≈ 190 m/s².

Then the tension in the rope is

<em>T</em> = (50 kg) <em>a</em> ≈ 9500 N.

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Answer:

Tissues that are damaged or injured.

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4 0
3 years ago
A charge q produces an electric field of strength 4E at a distance of d away. Determine the electric field strength at a distanc
gizmo_the_mogwai [7]

Answer:

c.) 36E

Explanation:

The magnitude of the electric field is given by the expression

E=k \frac{q}{d^2} (1)

where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.

In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

4E = k\frac{q}{d^2}

Now we want to determine the electric field at a distance of d'=\frac{1}{3}d away. Substituting into (1), we find

E' = k \frac{q}{d'^2}=k \frac{q}{(\frac{1}{3}d)^2}=9 k \frac{q}{d^2} (2)

We also know that

4E = k\frac{q}{d^2} (3)

So combining (2) with (3), we find a relationship between the original field and the new field:

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7 0
3 years ago
Pls help!! i don’t understand what i am supposed to do.
liq [111]

Well, my German isn't as sharp as it used to be, but it looks like you're supposed to use the symbols at the top and draw two circuits ... one where the switch is closed and the light is shining, the other where the switch is open and the light is out.

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A bullet is fired at a speed of 15 m/s from the edge of a cliff. The bullet strikes the ground 65 m from a height H. Find the fi
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Answer:

v=38.73m/s

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g=9.81

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