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Stels [109]
3 years ago
9

An object accelerates at 20 m/s2. By how much does the speed change in one second?

Physics
1 answer:
iren [92.7K]3 years ago
7 0

Explanation:

a= v/t

v= at

= 20m/s2 × 1sec

= 20m/s

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Holes are being steadily injected into a region of n-type silicon (connected to other devices, the details of which are not impo
Tems11 [23]

Complete Question

The  complete question is shown on the first  uploaded image

Answer:

The  value  is  J_n  =  -0.864 \  A/cm^2

Explanation:

Generally for an n-type semiconductor the current density is mathematically represented  as

         J_n  =  -q * d_p  *  \frac{d p_{n_o}}{d_w}

Here  p_{n_o} is mathematically represented as

          p_{n_o}  = \frac{n_i^2}{n_d}

=>      p_{n_o}  = \frac{(1.5*10^{10})^2}{10^{16}}

=>      p_{n_o}  = 2.25 *10^{4} \  cm^{-3}

So

    d p_{n_o} =  P_n0 - p_{n_o}

From the diagram  P_n0  =  10^8 * p_{n_o}

=>  P_n0  =  10^8 * (2.25 *10^{4} )

So

   d p_{n_o} =  10^8 * (2.25 *10^{4} ) - 2.25 *10^{4}

      d p_{n_o} =  2.25 *10^{12} cm^{-3}

So  from  J_n  =  -q * d_p  *  \frac{d p_{n_o}}{d_w}

substitute

    1.60 *10^{-19} \  C for  q  and  w_2 =50 nm =  50*10^{-9} m  =  5*10^{-6} cm

and from the diagram  w_1 =0 \ cm

So

    J_n  =  -1.60 *10^{-19} *12 *  \frac{2.25 *10^{12} }{ 5*10^{-6} - 0 }

    J_n  =  -0.864 \  A/cm^2

6 0
3 years ago
A 0.35-kgkg cord is stretched between two supports, 7.4 mm apart. When one support is struck by a hammer, a transverse wave trav
Agata [3.3K]

Answer:

The tension in the string is T = 1.49*10^{-6}N.

Explanation:

For a string with tension T and linear density \mu_d carrying a transverse wave at speed v it is true that

v = \sqrt{\dfrac{T}{\mu_d} }

solving for T we get:

T = \dfrac{v^2}{\mu_d}.

Now, the transverse wave covers the distance of 7.4mm in 0.88s, which means it's speed is

v =\dfrac{7.4*10^{-3}m}{0.88s} \\\\v = 8.4*10^{-3}s

And it's linear density (mass per unit length) is

\mu_d = \dfrac{0.35kg}{7.4*10^{-3}m} \\\\\mu_d = 47.3kg/m

Therefore, the tension in the cord is

T = \dfrac{(8.4*10^{-3}m/s^2)^2}{47.3kg/m}.

\boxed{T = 1.5*10^{-6}N}

or in micro newtons

T =1.5\mu N

4 0
3 years ago
IF a car trip 400 km in four hours what is the rate of speed that a car is traveling?
Andreas93 [3]

Speed = Distance/ Time

Speed = 400 / 4

Speed = 100 km/hr.

100 km per hour.
8 0
3 years ago
Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so
lisabon 2012 [21]

As per kinematics equation we are given that

v^2 = v_o^2 + 2ax

now we are given that

a = 2.55 m/s^2

v_0 = 21.8 m/s

v = 0

now we need to find x

from above equation we have

0^2 = 21.8^2 + 2(2.55)x

0 = 475.24 + 5.1 x

x = 93.2 m

so it will cover a distance of 93.2 m

7 0
3 years ago
Read 2 more answers
Electromagnetic radiation behaves both as particles (called photons) and as waves. Wavelength (λ) and frequency (ν) are related
inessss [21]
<h2>Answer: 136.363 m</h2>

Explanation:

We can find the wavelength of the radiation produced by the microwave oven by using the following given equation:

c=\lambda.\nu   (1)

Clearing \lambda :

\lambda=\frac{c}{\nu}   (2)

Knowing \nu=2.20 GHz=2.20(10)^{6}Hz=2.20(10)^{6}s^{-1}

\lambda=\frac{3(10)^{8}m/s}{2.20(10)^{6}s^{-1}}   (3)

\lambda=136.363m This is the wavelength of the radiation produced by the microwave

8 0
3 years ago
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