Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m
Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²
Let v = speed of pumping the gasoline, m/s
Then the mass flow rate is
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s
The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s
Answer: 2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
Answer:
d)21.5 moles
Explanation:
Given that
L = 24 L
T = 27 °C = 300 K
P = 22 atm
We know that ideal gas equation
P V = n R T
P=Pressure ,V= Volume ,n=Moles ,R=Universal gas constant ,T=Temperature
Now by putting the values
22 x 24 = n x 0.08206 x 300
n= 21.447 moles
n= 21.5 moles
Therefore the number of moles will be 21.5 moles.
The answer is "d".
Answer:
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Explanation:
Answer:
All of the above.
Explanation:
All Machines make work easier.
They can move objects.
They have multiple parts.
And the use energy.
Neap tide = tide where there is the least difference between high and low water levels
Spring tide = tide where there is the greatest difference between high and low water levels
Equator = an imaginary line drawn around earth dividing it into northern and southern hemispheres
Seasons = the divisions of the year marked by specific weather patterns and daylight hours.
Hope this helps!
