Answer:
1.05 J.
Explanation:
Kinetic Energy: This is the energy possessed by a body due to its motion. The S.I unit of kinetic energy is Joules (J). The formula of kinetic energy is given as
Ek = 1/2mv²................. Equation 1
Where Ek = kinetic energy, m = mass of the uniform rod, v = liner velocity of the rod.
But,
v = αr .......................... Equation 2
Where α = angular velocity of the rod, r = radius of the circle.
Given: α = 3.6 red/s, r = 120/2 = 60 cm = 0.6 m.
Substitute into equation 2
v = 3.6(0.6)
v = 2.16 m/s.
Also given: m = 450 g = 0.45 kg.
Substitute into equation 1
Ek = 1/2(0.45)(2.16²)
Ek = 1.05 J.
Answer:
(a) 2.33 A
(b) 15.075 V
Explanation:
From the question,
The total resistance (Rt) = R1+R2 = 3.85+6.47
R(t) = 10.32 ohms.
Applying ohm's law,
V = IR(t)..........equation 1
Where V = Emf of the battery, I = current flowing through the circuit, R(t) = combined resistance of both resistors.
Note: Since both resistors are connected in series, the current flowing through them is the same.
Therefore,
I = V/R(t)............. Equation 2
Given: V = 24 V, R(t) = 10.32 ohms
Substitute these values into equation 2
I = 24/10.32
I = 2.33 A.
Hence the current through R1 = 2.33 A.
V2 = IR2.............. Equation 3
V2 = 2.33(6.47)
V2 = 15.075 V
Answer: I would choose options C and D
Explanation:
Answer:
![\mu_k=\frac{a}{g}](https://tex.z-dn.net/?f=%5Cmu_k%3D%5Cfrac%7Ba%7D%7Bg%7D)
Explanation:
The force of kinetic friction on the block is defined as:
![F_k=\mu_kN](https://tex.z-dn.net/?f=F_k%3D%5Cmu_kN)
Where
is the coefficient of kinetic friction between the block and the surface and N is the normal force, which is always perpendicular to the surface that the object contacts. So, according to the free body diagram of the block, we have:
![N=mg\\F_k=F=ma](https://tex.z-dn.net/?f=N%3Dmg%5C%5CF_k%3DF%3Dma)
Replacing this in the first equation and solving for
:
![ma=\mu_k(mg)\\\mu_k=\frac{a}{g}](https://tex.z-dn.net/?f=ma%3D%5Cmu_k%28mg%29%5C%5C%5Cmu_k%3D%5Cfrac%7Ba%7D%7Bg%7D)