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mart [117]
2 years ago
15

How does the appearance of the protist differ from that of the onion sample?

Chemistry
1 answer:
lana [24]2 years ago
8 0

The appearance of the protist differ from that of the onion sample due to the presence of motile structures.

<h3>What is a Protist?</h3>

This is an eukaryote which could be unicellular or multicellular and examples include protozoa etc.

The major difference between a protist and onion sample is that protists have motile structures such as flagella, cilia etc while plant cells such as onions don't have.

Read more about Protist here brainly.com/question/2169979

#SPJ1

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uranmaximum [27]

Answer:

B - CALCIUM

Explanation:

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6 0
3 years ago
(Please help!)
Inessa [10]

Answer:

B. temperature decreases as altitude increases.

Explanation:

Just like in the lower reaches of the atmosphere, the troposphere, in the mesosphere, temperature decreases as altitude increases.

The mesosphere is the third layer of the atmosphere just above the stratosphere.

  • It begins at the top of the stratosphere and ends at the mesopause where the thermosphere begins.
  • The mesosphere is often referred to as the middle layer.

With increasing height, the temperature of the mesosphere decreases significantly. The top of the mesosphere is one of the coldest part of the earth atmosphere. This is as a result of increasing atmospheric cooling by carbon dioxide in this region of the atmosphere.

7 0
3 years ago
4NH3+5O2-4NO+6H2O<br>how many moles of NH3 must react to produce 5.0 moles of NO?​
tresset_1 [31]

Answer: 5.0 moles

Explanation:

From the equation, we see that for every 4 moles of ammonia consumed, 4 moles of nitrogen monoxide are produced (we can reduce this to moles of ammonia consumed = moles of nitrogen monoxide produced).

This means that the answer is <u>5.0 mol</u>

7 0
1 year ago
An Argon laser gives off pulses of green light (wavelength = 514 nm). If a single pulse from the laser has a total energy of 10.
svetoff [14.1K]

Answer:

n=2.59\times 10^{16} photons

Explanation:

E=n\times \frac{h\times c}{\lambda}

Where,  

n is the number of photons

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light

Given that, wavelength = 514 nm = 514\times 10^{-9}\ m

Energy = 10.0 mJ = 0.01 J ( 1 mJ = 0.001 J )

Applying the values as:-

0.01=n\times \frac{6.626\times 10^{-34}\times 3\times 10^8}{514\times 10^{-9}}

\frac{19.878n}{10^{17}\times \:514}=0.01

n=2.59\times 10^{16} photons

7 0
2 years ago
I need this please my brain hurts
GarryVolchara [31]
8.4 grams. I think but I’m not 100% sure
5 0
3 years ago
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