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2 years ago

Cuál es la característica principal para que un elemento sea radiactivo?

1 answer:

3 0

Definimos la radiactividad como el proceso mediante el cual un núcleo inestable pierde energia mediante emisiones (puede emitir fotones, neutrones, etc.)

Así, la característica princpial es que el elemento debe ser inestable.

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Cuando tenemos un elemento inestable, lo que puede deberse a que el elemento tiene un núcleo muy grande, o a que el elemento por alguna razón tiene muchos neutrones, este elemento querrá de alguna manera volver a un estado más estable.

Usualmente, la inestabilidad se ve representada como un dado exceso de energía, entonces la forma en la que el átomo se estabiliza es liberando energía de alguna forma.

Esta energía puede ser liberada mediante una desintegración, donde el elemento original se convierte en otros elementos y en el proceso se liberan nucleones, o por emisiones de fotones característicos del elemento, o de otras diversas formas que dependerán del caso particular.

Concluyendo la idea, para que un elemento sea radiactivo (es decir, emite radiación) la característica que este elemento debe tener es que debe ser inestable.

Sí quieres aprender más, puedes leer.

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Answer:

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Explanation:

Step 1: Data given

Mass of the sample = 1. 05 grams

The sample is 40.00% by mass NaNO2

MW of NaCl = 58.45 g/mol

MW of NaNO2 = 69.01 g/mol

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The vapor pressure of water at 22.0°C is 19.8 mm Hg = 0.02605 atm

Step 2: Calculate mass of NaNO2

(40/100)*1.05 = 0.42 grams

Step 3: Calculate moles of NaNO2

Moles NaNO2 = 0.42 grams / 69.01 g/mol

Moles NaNO2 = 0.00608 moles

Step 4: Calculate moles of N2

For 2 moles of NaNO2 we'll get 1 mol of N2

For 0.00608 moles of NaNO2 we'll get 0.00608/2 = 0.00304 moles

Step 5: Calculate pressure of N2

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Step 6: Calculate volume of N2

PV = nRT

⇒ P = the pressure of N2 = 0.96079

⇒ V = the volume of N2 = TO BE DETERMINED

⇒ n = moles of N2 = 0.00304 moles

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 22°C = 295 Kelvin

V = (0.00304*0.08206*295)/0.96079

V = 0.0766 L = 76.6 mL

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