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2 years ago

The energy diagram illustrated in the model corresponds to what student B

Chemistry

1 answer:

KatRina [158]2 years ago

4 0

Answer: Exothermic reaction

Explanation:

Exothermic reactions lose energy, or ΔH, when they react.

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Calculate the Standard Enthalpy of the reaction below:

Norma-Jean [14]

Answer:

(we use hess's law) it is so simple but the second reaction is not correct please right it

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2 years ago

why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis

Helga [31]

Answer:

Plasmas of great interest to scientists or manufacturers as

Plasma is electrically charged gases that contain considerable charged particles that can change the behavior of the substance.

Current uses of plasmas:

First, it is used to make semiconductors for different types of electronic equipment

Secondly, they're used in making transmitters for high-temperature films.

Way scientists and engineers hope to use plasmas in the future:

The scientists are hoping to use plasma in the future to get rid of all hazardous wastes through a process called plasma gasification.

6 0

2 years ago

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

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2 years ago

Which hydrogen atom would be most easily extracted by a bromine atom?

DerKrebs [107]

The proton which is easily abstracted in 1-Benzyl-3-propylbenzene is the proton which is present on carbon atom in between two phenyl rings, or the central carbon which is shared by two benzene rings.

This easy abstraction of proton is due to its high acidity. Remember those species are always more acidic whose conjugate base is stable. Like the acidity of carboxylic acid is due to stability of the acetate ion.

In our case the stability of conjugate base arises due to stability of negative ion due to resonance. As shown below, the negative charge can delocalize on both rings.

I have shown the resonance of negative ion on both Phenyl rings with Blue and Pink colors.

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2 years ago

Calcium reacts with oxygen to form calcium oxide. Name the reactants.

LUCKY_DIMON [66]

CaO
Calcium reacts with oxygen to form calcium oxide. The chemical equation for this reaction is Ca + O2 → CaO.

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2 years ago