You can determine this by counting the number of electrons on the last orbital. If the number of electrons on the last orbital (valence electrons) is 8 then it satisfies the octet rule because the compound has mirrored the look of a noble gass or “neutral” charge.
Hey there!:
Molar mass AgNO3 = 169.87 g/mol
Number of moles:
moles of solution = mass of solute / molar mass
moles of solution = 18.7 / 169.87
moles of solution = 0.110084 moles of AgNO3
Volume in liters:
250.0 mL / 1000 => 0.25 L
Therefore:
Molarity = moles of solution / Volume of solution ( L )
Molarity = 0.110084 / 0.25
=> 0.440 M
Hope that helps!
Answer:
Entropy increases
Explanation:
Entropy (S) is a measure of the degree of disorder. For a given substance - say water - across phases the following is true ...
S(ice) < S(water) << S(steam)
For a chemical process, entropy changes can be related to increasing or decreasing molar volumes of gas from reactant side of equation to product side of equation. That is ...
if molar volumes of gas increase, then entropy increases, and
if molar volumes of gas decrease, then entropy decreases.
For the reaction 2KClO₃(s) => 2KCl(s) + 3O₂(g)
molar volumes of gas => 0Vm* 0Vm 3Vm
*molar volumes (Vm) apply only to gas phase substances. Solids and liquids do not have molar volume.
Since the reaction produces 3 molar volumes of O₂(g) product vs 0 molar volumes of reactant, then the reaction is showing an increase in molar volumes of gas phase substances and its entropy is therefore increasing.
Answer:
at the top of the swing
at the top of the swing
at the bottom of the swing
at the bottom of the swing
Explanation:
<u>Answer:</u> The net ionic equation is written below.
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of ammonium carbonate and lead (II) nitrate is given as:
Ionic form of the above equation follows:
As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the net ionic equation is written above.
