<span>it must be a compound of a polyatomic cation (i think ammonium might be the only</span>
Answer:
Hexanol has the highest boiling point.
Explanation:
Boiling points of all give compounds are as follow,
Hexanol = 157 °C
Hexanal = 129 °C
Hexanone = 128 °C
Hexane = 68 °C
Types of Interactions found in these compounds are,
Hexanol = Hydrogen Bonding & London Dispersion Forces
Hexanal = Dipole-Dipole Interactions & London Dispersion Forces
Hexanone = Dipole-Dipole Interactions & London Dispersion Forces
Hexane = Only London Dispersion Forces
Strength of Intermolecular Forces:
Hydrogen forces are stronger than Dipole-Dipole Interactions, and Dipole-Dipole Interactions are stronger than London Dispersion Forces.
Result:
Hence, due to presence of strong Hydrogen Bond Interactions Hexanol has the highest Boiling Point.
Answer:
What forms of energy does a burning candle give out?
- The burning candle is converting chemical energy—stored in the hydrocarbon bonds in the wax—into thermal (heat) and radiant (light) energy.
What questions do you have about energy?
- Can momentum be hidden to human eyes like how kinetic energy can be hidden as heat?
- Can you go fast enough to get enough mass to become a black hole?
- How can a material at a certain temperature have all of its molecules at the same energy?
- How can we travel to the past?
Answer:
Option d.
1 mole AlCl3in 500 g water
Explanation:
ΔT = Kf . m . i
Freezing T° of solution = - (Kf . m . i)
In order to have the lowest freezing T° of solution, we need to know which solution has the highest value for the product (Kf . m . i)
Kf is a constant, so stays the same and m stays also the same because we have the same moles, in the same amount of solvent. In conclussion, same molality to all.
i defines everything. The i refers to the Van't Hoff factor which are the number of ions dissolved in solution. We assume 100 & of ionization so:
a. Glucose → i = 1
Glucose is non electrolytic, no ions formed
b. MgF₂ → Mg²⁺ + 2F⁻
i = 3. 1 mol of magnessium cation and 2 fluorides.
c. KBr → K⁺ + Br⁻
i = 2. 1 mol potassium cation and 1 mol of bromide anion
d. AlCl₃ → Al³⁺ + 3Cl⁻
i = 4. 1 mol of aluminum cation and 3 mol of chlorides.
Kf . m . 4 → option d will has the highest product, therefore will be the lowest freezing point.
