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3 years ago

What is the molality of solution prepared by dissolving 21.7g KCl in 225g of water?

Chemistry

2 answers:

notka56 [123]3 years ago

5 0

Answer:

Explanation:

erastova [34]3 years ago

4 0

The answer to your question will be D. 1.29m

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Amphetamine was developed initially as a substitute for a closely-related chemical derived from the Chinese herb ma huang. That

Zepler [3.9K]

Amphetamine was developed initially as a substitute for a closely-related chemical derived from the Chinese herb ma huang. That chemical is Ephedrine.

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2 years ago

Forensic toxicology involves not only the area of toxicology, but also the use of areas such as analytic chemistry and pharmacol

grandymaker [24]

Answer:

The answer is True

Explanation:

Forensic toxicology involves or employs or uses disciplines such as analytical chemistry, pharmacology and clinical chemistry to aid medical or legal investigation.

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3 years ago

Read 2 more answers

A student investigated how much solid was dissolved in sea water.

SashulF [63]

Answer:

weighing balance/analytical balance

Graduated cylinder/buret

Explanation:

The mass of the evaporating basin could be measured using a weighing balance or an analytical balance. Both are classified as weighing scales but the analytical balance can measure the mass of objects up to 4 decimal places, thus, providing better accuracy in measurement than ordinary weighing balance that can only measure up to 2 decimal places.

In order to measure 50 cm3 of the sea water, a graduated cylinder or a buret can be used. Both equipment can measure up to the same decimal places and, thus, have virtually the same accuracy.

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3 years ago

When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC = C = 0,50 J/gºC

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3 years ago

Uniones que se dan entre atomo y moleculas

lesya [120]

Answer:

khbfd skjb skbusf szkbs

Explanation:jdfh sms kok

6 0

3 years ago