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3 years ago

How many significant figures are in the measurement 81,140 grams

Chemistry

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

Explanation:

In order to be able to say how many sig figs are used for the measurement 811.40 g, you need to know that

non-zero digits are always significanta trailing zero that follows a decimal point and a non-zero digit is always significant

In your case, the measurement

811.40

has four non-zero digits and one significant trailing zero.

8,1,1,4→ non-zero digits8,1,1,0→ significant trailing zero

Therefore, you can say that this measurement has five significant figures

811.40→ five significant figures

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78.5 mol of P4O10 contains how many moles of P?

MArishka [77]

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3 years ago

Where would you look for igneous rocks? Why?

Brut [27]

Answer:

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Explanation: im pretty sure thats right at least

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3 years ago

Can someone help please

Serhud [2]

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2 years ago

Read 2 more answers

For a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k, calculate the inner diameter if you are designing for

bonufazy [111]

The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m

<h3>What is Stack Height ?</h3>

Stack height means the distance from the ground-level elevation at the base of the stack to the crown of the stack.

If a stack arises from a building or other structure, the ground-level elevation of that building or structure will be used as the base elevation of the stack.

Given is a steel stack that exhausts 1,200 cu.m/min of gases

P= 1 atm and

T= 400 K

maximum expected wind speed at stack height of 12 m/s

The formula for the diameter of chimney

$\rm d=\sqrt{\dfrac{4Q}{\pi v} }$

Q =1200 cu.m/min

= 1200 * 0.0166 = 19.92 cu.m/sec

Velocity = 12m/s

$\rm d=\sqrt{\dfrac{4\times 19.92}{3.14*12} }\\$

d= 1.45 m

Therefore The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m.

To know more about Stack Height

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8 0

2 years ago

g Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equ

ipn [44]

Answer:

0.719M AgNO₃

Explanation:

Based on the reaction:

MgBr₂ + 2AgNO₃ ⇄ 2AgBr + Mg(NO₃)₂

1 mole of magnesium bromide reacts completely with 2 moles of AgNO₃

To find molarity of AgNO₃ solution we need to determine moles of AgNO₃ and, as molarity is the ratio of moles over liter (13.9mL = 0.0139L). Now, to determine moles of AgNO₃ we need to use the reaction, thus:

Moles AgNO₃:

Moles of MgBr₂ are:

50.0mL = 0.050L * (0.100mol / L) = 0.00500 moles of MgBr₂.

As the silver nitrate reacts completely and 2 moles of AgNO₃ reacts per mole of MgBr₂:

0.00500 moles MgBr₂ * (2 moles AgNO₃ / 1 mole MgBr₂) =

0.0100 moles of AgNO₃ are in the solution.

And molarity is:

0.0100 moles AgNO₃ / 0.0139L =

3 0

2 years ago