Question

how many moles of oxygen are in a 7.68L container at 355k and exerting a pressure of 8.57atm on the walls of the container

Answer 1

We can use the Ideal Gas Law for this question:

$PV=nRT$

So we need to solve the equation for n, the number of moles:

$\frac{PV}{RT}=n$

Now we can plug in the values that we are given to solve for the number of moles:

$\frac{(8.57atm)(7.68L)}{(\frac{0.0821 L *atm}{mol* K} )(355K)}=n$

$\frac{65.8176}{29.1455} =n=2.26$

So now we know that there are 2.26 moles of oxygen in the container.

Answer 2

Explanation:

It is given that volume is 7.68 L, temperature is 355 k and pressure is 8.57 atm. So, according to ideal gas equation PV = nRT.

Also, it is known that number of moles equal mass divided by molar mass.

Therefore, putting the given values into the ideal gas equation as follows.

                      PV = nRT

   $8.57 atm \times 7.68 L$ = $n \times 0.082 atm L/mol K \times 355 K$

                             n = 2.26 mol

Thus, we can conclude that the number of moles present in given oxygen is 2.26 mol.