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3 years ago

how many moles of oxygen are in a 7.68L container at 355k and exerting a pressure of 8.57atm on the walls of the container

Chemistry

2 answers:

mart [117]3 years ago

5 0

We can use the Ideal Gas Law for this question:

$PV=nRT$

So we need to solve the equation for n, the number of moles:

$\frac{PV}{RT}=n$

Now we can plug in the values that we are given to solve for the number of moles:

$\frac{(8.57atm)(7.68L)}{(\frac{0.0821 L *atm}{mol* K} )(355K)}=n$

$\frac{65.8176}{29.1455} =n=2.26$

So now we know that there are 2.26 moles of oxygen in the container.

aev [14]3 years ago

3 0

Explanation:

It is given that volume is 7.68 L, temperature is 355 k and pressure is 8.57 atm. So, according to ideal gas equation PV = nRT.

Also, it is known that number of moles equal mass divided by molar mass.

Therefore, putting the given values into the ideal gas equation as follows.

PV = nRT

$8.57 atm \times 7.68 L$ = $n \times 0.082 atm L/mol K \times 355 K$

n = 2.26 mol

Thus, we can conclude that the number of moles present in given oxygen is 2.26 mol.

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<h2>Answer:</h2>

Arrangement of inter molecular forces from strongest to weakest.

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Hydrogen bonding is a type of dipole dipole interaction between the positive charge hydrogen ion and the slightly negative pole of a molecule. For example H---O bonding between water molecules.

Dipole dipole interactions are also attractive interactions between the slightly positive head of one molecule and the negative pole of other molecules.

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3 years ago

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Answer:

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Explanation:

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2 years ago

A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83

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Answer:

a. 478.69 K

b. 939.43 $cm^{3}$

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

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$T_{o}$ = 400K

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where R is the molar gas constant = 8.314 $m^{3}$ ⋅Pa⋅ $K^{-1}$ ⋅ $mol^{-1}$

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

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To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

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83.8 = 0.03 × [34980 + 35.5 $T_{1}$ - (34980 + 35.5 $T_{o}$ )]

83.8 = (0.03 × 35.5) ( $T_{1}$ - 400K)

83.8 = 1.065 ( $T_{1}$ - 400)

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$T_{1}$ = 400 + 78.69

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To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

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$V_{1}$ = $V_{o}$ $T_{1}$ / $T_{o}$

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c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P( $V_{1}$ - $V_{o}$ ) = 125 KPa ( 939.43 - 785) = 19.30 J

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