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Drupady [299]
3 years ago
6

What is the ionic equation for dilute hydrochloric acid and magnesium

Chemistry
2 answers:
Nataly [62]3 years ago
7 0

Answer:

Mg(s) + 2H⁺(aq) ⟶ Mg²⁺(aq) + H₂(g)  

Explanation:

A net ionic equation shows all the ionic substances as ions and shows the correct state of each substance.

valentina_108 [34]3 years ago
4 0

Magnesium react with hydrochloric acid according to the equation :

<h3> Mg(s)+2HCL(aq)-----><em>MgCL2</em><em>(</em><em>aq</em><em>)</em><em> </em><em>+</em><em>H2</em><em>(</em><em>g</em><em>)</em></h3>

This demonstration can be used to illustrate the characteristics reactions of metals with acid , a single replacement reaction ,or to demonstrate the generation of hydrogen gas.

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Sodium carbonate (NaCO3) is sometimes used as a water-softening agent. Suppose that a worker prepares a 0.730 M solution of NaCO
elena55 [62]

Answer : The mass of solute in solution is 1.09\times 10^2g.

Solution : Given,

Molarity = 0.730 M

Volume of solution = 1.421 L

Molar mass of sodium carbonate = 105.98 g/mole

Formula used for Molarity :

Molarity=\frac{w}{M\times V}

where,

w = mass of solute

M = Molar mass of solute

V = volume of solution in liter

Sodium carbonate is solute and water is solvent.

Now put the given values in above formula, we get the mass of solute in solution.

0.730mole/L=\frac{w}{(105.98g/mole)\times (1.412L)}

By rearranging the terms, we get

m=109.247g=1.09\times 10^2g

Therefore, the mass of solute in solution is 1.09\times 10^2g.

4 0
3 years ago
Explain how the bonding model for sodium metal would differ from the bonding model for sodium chloride, NaCi
Elina [12.6K]
Sodium metal is quite reactive; sodium ions (as in NaCl) are quite unreactive. Cl^- ions are not reactive; they are stingily attracted to positive ions such as Na^+with which they form ionic bonds.
8 0
3 years ago
Human reaction time is usually about 0.18 s. If your lab partner holds a ruler between your finger and thumb and releases it fro
Marizza181 [45]

Answer:

–0.16 m

Explanation:

From the question given above, the following data were obtained:

Time (t) = 0.18 s

Acceleration due to gravity (g) = –9.81 m/s²

Height (h) =?

We can obtain how far the ruler will fall by using the following equation:

H = ½gt²

H = ½ × –9.81 × 0.18²

H = ½ × –9.81 × 0.0324

H = –0.16 m

Thus, the ruler will fall –0.16 m before you will catch it.

7 0
2 years ago
The American Council for an Energy Efficient Economy works to _______.
Komok [63]
<span>The American Council for an Energy-Efficient Economy works to (c) </span>invest in clean energy technologies that will strengthen the economy.

Their aim is to promote energy efficiency which will ultimately benefit the economy and the environment. 
8 0
3 years ago
Read 2 more answers
Ca(OH)2 (s) precipitates when a 1.0 g sample of CaC2(s) is added to 1.0 L of distilled water at room temperature. If a 0.064 g s
Nina [5.8K]

Answer:

D) Ca(OH)₂ will not precipitate because Q <  Ksp

Explanation:

Here we have first a chemical reaction in which Ca(OH)₂  is produced:

CaC₂(s)  + H₂O ⇒ Ca(OH)₂ + C₂H₂

Ca(OH)₂  is slightly soluble, and depending on its concentration it may precipitate out of solution.

The solubility product  constant for Ca(OH)₂  is:

Ca(OH)₂(s) ⇆ Ca²⁺(aq) + 2OH⁻(aq)

Ksp = [Ca²⁺][OH⁻]²

and the reaction quotient Q:

Q = [Ca²⁺][OH⁻]²

So by comparing Q with Ksp we will be able to determine if a precipitate will form.

From the stoichiometry of the reaction we know the number of moles of hydroxide produced, and since the volume is 1 L the molarity will also be known.

mol Ca(OH)₂ = mol CaC₂( reacted = 0.064 g / 64 g/mol = 0.001 mol Ca(OH)₂

the concentration of ions will be:

[Ca²⁺ ] = 0.001 mol / L 0.001 M

[OH⁻] = 2 x 0.001 M  = 0.002 M  ( From the coefficient 2 in the equilibrium)

Now we can calculate the reaction quotient.

Q=  [Ca²⁺][OH⁻]² = 0.001 x (0.002)² = 4.0 x 10⁻⁹

Q < Ksp since 4.0 x 10⁻⁹ < 8.0 x 10⁻⁸

Therefore no precipitate will form.

The answer that matches is option D

8 0
3 years ago
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