1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25
2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180 180-154=2f=26 angle f=13 QPR=13
3. so we assume that BG is straight so it is 180 we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x 5x=55 x=11 CQD=2x=22 EQF=3x=33
4. we know that x=x and the whole is 360 so x+x+x+x+71+71+71+71=360=4x+284=360 4x=76 x=19
8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so 99=3x CQG=99
9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20 20*4=80 20*5=100 4:5 =80:100
a. 80 and 100 b. you should be able to do this
10. so on a line is 180 a. 3:4:5 3+4+5=12 180/12=15 3*15=45 4*15=60 5*15=75 3:4:5 =45:60:75 the angles are 45 60 75
