Question

A soccer player is running upfield at 10m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleration?

Answer 1

Answer : His acceleration is, $-3.3m/s^2$

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 0 m/s

u = initial velocity  = 10 m/s

t = time = 3 s

a = acceleration = ?

Now put all the given values in the above equation 1, we get:

$0m/s=10m/s+a\times (3s)$

$a=-3.3m/s^2$

Therefore, his acceleration is, $-3.3m/s^2$

Answer 2

The players acceleration is 3.33 m/s/s

Acceleration= Velocity/Time

A =10/3