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dlinn [17]
4 years ago
5

What are Vertical columns on the periodic table called

Physics
2 answers:
alexgriva [62]4 years ago
5 0
Vertical columns are groups or families
Yanka [14]4 years ago
4 0
The vertical collumns are called groups or families.
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20-kilogram canoe is floating downriver at 2 m/s. what’s the kinetic energy?
ziro4ka [17]

Answer:

40J

Explanation:

Kinetic energy = 1/2 mv^2

Where m = mass and

v = velocity

Given mass = 20kg

v = 2m/s

K.E = 1/2 x 20 x2^2

= 1/2 x 20 x 2 x 2

= 80/2

= 40J

6 0
3 years ago
Read 2 more answers
If the sun suddenly ceased to shine, how long would it take earth to become dark? you will have to look up the speed of light in
sleet_krkn [62]
We are 8 light minutes from the sun. That means two things, we see the sun as it was 8 minutes ago, and we WOULD continue to see the sun for 8 minutes after it disappeared.
3 0
3 years ago
Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest-accelerating animals,
erik [133]

Answer:

Explanation:

given,

speed of cheetah = 27 m/s

time taken  = 4 s

mass of cheetah = 110 kg

a = \dfrac{27-0}{4}

a = 6.75 m/s²

v² = u² + 2 as

27² = 0 + 2 × 6.75× s

s = 54 m

a) power = \dfrac{work\ done}{t}

power = \dfrac{F.s}{t}

power = \dfrac{m.a.s}{t}

power = \dfrac{110\times 6.75\times 54}{4}

power = 10,023\ watt

b) power = \dfrac{10,023}{746}

   power = 13.46\ horsepower

5 0
3 years ago
The local weather in regions where sea or lake shores are presents is a affected by the properties of water
____ [38]

Answer:

gulf

Explanation:

3 0
4 years ago
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
Anni [7]

Answer:

0.074m/s

Explanation:

We need the formula for conservation of momentum in a collision, this equation is given by,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Where,

m_1 = mass of ball

m_2 = mass of the person

u_1 = Velocity of ball before collision

u_2 = Velocity of the person before collision

v_1 = velocity of ball afer collision

v_2= velocity of the person after collision

We know that after the collision, as the person as the ball have both the same velocity, then,

v_1 = v_2

m_1u_1 + m_2u_2 = (m_1+m_2)v_2

Re-arrenge to find v_2,

v_2 = \frac{m_1u_1+m_2u_2}{m_1+m_2}

Our values are,

m_1= 0.425kg

u_1= 12m/s

m_2= 68.5kg

u_2= 0m/s

Substituting,

v_2 = \frac{(0.425)(12)+(68.5)(0)}{0.425+68.5}

v_2 = 0.074m/s

<em />

<em>The speed of the person would be 0.074m/s after the collision between him/her and the ball</em>

7 0
3 years ago
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