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4 years ago

What are Vertical columns on the periodic table called

Physics

2 answers:

alexgriva [62]4 years ago

5 0

Vertical columns are groups or families

Yanka [14]4 years ago

4 0

The vertical collumns are called groups or families.

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20-kilogram canoe is floating downriver at 2 m/s. what’s the kinetic energy?

ziro4ka [17]

Answer:

40J

Explanation:

Kinetic energy = 1/2 mv^2

Where m = mass and

v = velocity

Given mass = 20kg

v = 2m/s

K.E = 1/2 x 20 x2^2

= 1/2 x 20 x 2 x 2

= 80/2

= 40J

6 0

3 years ago

Read 2 more answers

If the sun suddenly ceased to shine, how long would it take earth to become dark? you will have to look up the speed of light in

sleet_krkn [62]

We are 8 light minutes from the sun. That means two things, we see the sun as it was 8 minutes ago, and we WOULD continue to see the sun for 8 minutes after it disappeared.

3 0

3 years ago

Multiple-Concept Example 13 presents useful background for this problem. The cheetah is one of the fastest-accelerating animals,

erik [133]

Answer:

Explanation:

given,

speed of cheetah = 27 m/s

time taken = 4 s

mass of cheetah = 110 kg

$a = \dfrac{27-0}{4}$

a = 6.75 m/s²

v² = u² + 2 as

27² = 0 + 2 × 6.75× s

s = 54 m

a) $power = \dfrac{work\ done}{t}$

$power = \dfrac{F.s}{t}$

$power = \dfrac{m.a.s}{t}$

$power = \dfrac{110\times 6.75\times 54}{4}$

$power = 10,023\ watt$

b) $power = \dfrac{10,023}{746}$

$power = 13.46\ horsepower$

5 0

3 years ago

The local weather in regions where sea or lake shores are presents is a affected by the properties of water

____ [38]

Answer:

gulf

Explanation:

3 0

4 years ago

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between

Anni [7]

Answer:

0.074m/s

Explanation:

We need the formula for conservation of momentum in a collision, this equation is given by,

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

Where,

$m_1$ = mass of ball

$m_2$ = mass of the person

$u_1$ = Velocity of ball before collision

$u_2$ = Velocity of the person before collision

$v_1$ = velocity of ball afer collision

$v_2$ = velocity of the person after collision

We know that after the collision, as the person as the ball have both the same velocity, then,

$v_1 = v_2$

$m_1u_1 + m_2u_2 = (m_1+m_2)v_2$

Re-arrenge to find $v_2$ ,

$v_2 = \frac{m_1u_1+m_2u_2}{m_1+m_2}$

Our values are,

$m_1$ = 0.425kg

$u_1$ = 12m/s

$m_2$ = 68.5kg

$u_2$ = 0m/s

Substituting,

$v_2 = \frac{(0.425)(12)+(68.5)(0)}{0.425+68.5}$

$v_2 = 0.074m/s$

<em />

<em>The speed of the person would be 0.074m/s after the collision between him/her and the ball</em>

7 0

3 years ago