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3 years ago

How many atoms of oxygen in 4 molecules of HNO3?

Chemistry

2 answers:

DaniilM [7]3 years ago

8 0

Answer:12

Explnation:

MrRissso [65]3 years ago

4 0

Answer:

12 oxygen atoms are in 4 molecules of HNO3?

Explanation:

the amounts of atoms of all the component in HNO3, which are 1 atom of Hydrogen, 1 atom of Nitrogen and 3 atoms of Oxygen.

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Suppose that 100 grams of water at 50.0°C is placed in contact with 200 grams of iron at 30.0°C. The final

wel

Answer:

The answer would be 1.5 kJ.

Explanation:

When you use the equation q = m x c x ∆T you will be able to find the energy gained or lost. The data for the water in this case is just there to distract you so ignore it. :D

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3 years ago

Why do molecular compounds have low melting points and low boiling points relative to ionic substances?

kap26 [50]

Answer:

The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound

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3 years ago

Sam believes the rock is more denser than the pencil. He measured the mass of the rock to be 8.5 grams and volume to be 4.5mL. H

mezya [45]

Answer:

Rock

Explanation:

Let's calculate the density of each object:

Rock:

$Density = \frac{mass}{volume}=\frac{8.5\ g}{4.5\ mL}=1.9\ g/mL$

Pencil:

$Density = \frac{mass}{volume}=\frac{2.4\ g}{4.5\ mL}=0.53\ g/mL$

Therefore the rock is denser.

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3 years ago

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4 years ago

Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,

djverab [1.8K]

Answer: The reaction proceeds in the forward direction

Explanation:

For the given chemical equation:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

Relation of $K_p\text{ with }K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $6.5\times 10^4$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $35^oC=[35+273]K=308K$

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43$

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.