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Nookie1986 [14]
3 years ago
11

What will you suggest to a person who is suffering from the problem of acidity after overeating?

Chemistry
2 answers:
Bumek [7]3 years ago
3 0

Answer:

If someone is suffering from the problem of acidity after overeating Baking soda solution would be suggested as a remedy as it is basic in nature, it neutralises excess acid in the stomach.

uranmaximum [27]3 years ago
3 0
If someone is suffering from the problem of acidity after overeating Baking soda solution would be suggested as a remedy as it is basic in nature, it neutralises excess acid in the stomach. Lemon juice, Vinegar, Baking soda solution.
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How many moles are in 525 g of ammonia, NH3?<br> 8940.75 M<br> 0.03 M<br> 30.83 M
victus00 [196]

Answer:

30.83 M

Explanation:

17.03052 re in one mole. So, if you multiply it by 30.83, you will get 535 g of ammonia.

In fact, the detailed answer is 30.827009392549122.

3 0
2 years ago
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The molecular weight of a gas is ________ g/mol if 3.5 g of the gas occupies 2.1 l at stp
bija089 [108]
<span>Pre-1982 definition of STP: 37 g/mol Post-1982 definition of STP: 38 g/mol This problem is somewhat ambiguous because the definition of STP changed in 1982. Prior to 1982, the definition was 273.15 K at a pressure of 1 atmosphere (101325 Pascals). Since 1982, the definition is 273.15 K at a pressure of exactly 100000 Pascals). Because of those 2 different definitions, the volume of 1 mole of gas is either 22.414 Liters (pre 1982 definition), or 22.71098 liters (post 1982 definition). And finally, there's entirely too many text books out there that still use the 35 year obsolete definition. So let's solve this problem using both definitions and you need to pick the correct answer for the text book you're using. First, determine how many moles of gas you have. Just simply divide the volume you have by the molar volume. Pre-1982: 2.1 / 22.414 = 0.093691443 moles Post-1982: 2.1 / 22.71098 = 0.092466287 moles Now determine the molar mass. Simply divide the mass by the moles. So Pre-1982: 3.5 g / 0.093691443 moles = 37.35666667 g/mol Post-1982: 3.5 g / 0.092466287 moles = 37.85163333 g/mol Finally, round to 2 significant figures. So Pre-1982: 37 g/mol Post-1982: 38 g/mol</span>
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3 years ago
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Answer:

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a student determined that 8.2 milligrams of oxygen is dissolved in a 1000 gram sample of water at 15 degrees Celsius and 1 atm w
melamori03 [73]

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10<br> 20<br> 30<br> 40<br> 50<br> 60<br> 70<br> 80<br> 90<br> 100g<br> 100<br> 200<br> 300<br> 400<br> 500g<br> 0<br> 1<br> 2<b
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