In the titration of lemon juice, the presence of ascorbic acid means the concentration of citric acid you calculated is higher.
An acid-base titration is a common way to determine the unknown concentration of an acid, given we know the concentration of the base and determine the spent volume in the titration. Let's consider the neutralization reactions that take place in a mixture of citric acid and ascorbic acid.
Citric acid titration :
3 NaOH(aq) + H₃C₆H₅O₇(aq) → Na₃C₆H₅O₇(aq) + 3 H₂O(l)
Ascorbic acid titration:
NaOH(aq) + HC₆H₇O₆(aq) → NaC₆H₇O₆(aq) + H₂O(l)
If we titrated a solution that contained only citric acid, we can relate through stoichiometry the moles and concentration of citric acid. However, if the solution also contained ascorbic acid, we would have to spend more NaOH to titrate it. Since more NaOH would react, we would conclude that there is more citric acid to react, calculating a higher concentration of the same.
In the titration of lemon juice, the presence of ascorbic acid means the concentration of citric acid you calculated is higher.
You can learn more about titration here: brainly.com/question/2728613
The answer is No. That is the mass of the sealed jar and its contents does not change upon the vaporization of the liquid, as according to the “law of conservation of mass” , the mass remain conserved when no matter is escape, the mass will remain constant and here also as the jar is sealed, no matter is escaped thus no mass change will be there.
Answer:
The correct answer is letter A. Condensation nucleii
The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is 2.08 atm.
<h3>What is the pressure?</h3>
In this problem, we are mandated to obtain the pressure both by the use of the ideal gas equation and then the use of the Van der Walls equation.
Using the idea gas equation;
PV = nRT
P = nRT/V
P = pressure
V = volume
n = number of moles
T = temperature
R = gas constant
P = 1 * 0.082 * (24 + 273)/0.5
P = 48.7 atm
Using the Van Der Wall equation:
P = RT/(V - b) - a /V^2
P = 0.082 * 297/(0.5 - 0.03219) - 1.345/(0.5)^2
P = 24.354/0.46781 - 1.345/ /0.25
P = 52 - 5.38
P = 46.62 atm
The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is; 48.7 atm - 46.62 atm = 2.08 atm
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