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ira [324]
2 years ago
10

How many formula units make up 11.8 g of Magnesium Chloride (MgCl2)

Chemistry
1 answer:
lions [1.4K]2 years ago
4 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

11.8 g ( 1 mol / 95.21 g ) ( 6.022 x 10^23 formula units / mol ) = 7.46 x10^22 formula units

Hope this answers the question. Have a nice day.

</span>
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Answer and Explanation:

Las fórmulas químicas sirven para conocer qué elementos químicos y en qué cantidad están presentes en un compuesto químico. Por ejemplo: la fórmula química del dióxido de carbono es CO₂. Esta fórmula nos indica que la molécula de dióxido de carbono está formada por 1 átomo del elemento químico carbono y 2 átomos del elemento oxígeno.

Los diferentes tipos de fórmulas químicas son: fórmula empírica, fórmula molecular, fórmula semi-desarrollada y fórmula desarrollada. Tomando como ejemplo al compuesto <em>butano</em>:

- Fórmula empírica: C₂H₅ (indica que hay 2 átomos de C por cada 5 átomos de H; es una fórmula mínima)

- Fórmula molecular: C₄H₁₀ (indica que en realidad cada molécula de butano tiene 4 átomos de C y 10 átomos de H).

- Fórmula semi-desarrollada: CH₃CH₂CH₂CH₃ (indica el órden en que se unen los átomos en la molécula).

-Fórmula desarrollada: ver dibujo adjunto (indica cómo están unidos los átomos dentro de la molécula. Ahora vemos los enlaces entre los átomos y que los 2 átomos de C de los extremos están unidos a 3 átomos de H y a otro C, y los dos átomos de C del medio están unidos cada uno a 2 C y 2 H).

8 0
2 years ago
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Answer:

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1. Metals are shiny but most non - metals lack this property.

2. Metals are able to deform under compression (malleable) but most non - metals lack this property.

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<u>2</u><u>.</u><u> </u><u>Metals</u><u>,</u><u> </u><u>when</u><u> </u><u>exposed</u><u> </u><u>to</u><u> </u><u>water</u><u> </u><u>atmospheric</u><u> </u><u>oxygen</u><u> </u><u>tend</u><u> </u><u>to</u><u> </u><u>rust</u><u> </u><u>but</u><u> </u><u>non</u><u> </u><u>-</u><u> </u><u>metals</u><u> </u><u>lack</u><u> </u><u>this</u><u> </u><u>chemical</u><u> </u><u>property</u>

7 0
3 years ago
Which of the following is an example of a
Sergio039 [100]

Answer:

dissolving sugar into water is a physical change

5 0
2 years ago
A flask contains 6g hydrogen gas and 64 g oxygen at rtp the partial pressure of hydrogen gas in the flask of the total pressure
Alex

Answer:

B.3/5p

Explanation:

For this question, we have to remember <u>"Dalton's Law of Partial Pressures"</u>. This law says that the pressure of the mixture would be equal to the sum of the partial pressure of each gas.

Additionally, we have a <em>proportional relationship between moles and pressure</em>. In other words, more moles indicate more pressure and vice-versa.

P_i=P_t_o_t_a_l*X_i

Where:

P_i=Partial pressure

P_t_o_t_a_l=Total pressure

X_i=mole fraction

With this in mind, we can work with the moles of each compound if we want to analyze the pressure. With the molar mass of each compound we can calculate the moles:

<u>moles of hydrogen gas</u>

The molar mass of hydrogen gas (H_2) is 2 g/mol, so:

6g~H_2\frac{1~mol~H_2}{2~g~H_2}=~3~mol~H_2

<u>moles of oxygen gas</u>

The molar mass of oxygen gas (O_2) is 32 g/mol, so:

64g~H_2\frac{1~mol~H_2}{32~g~H_2}=~2~mol~O_2

Now, total moles are:

Total moles = 2 + 3 = 5

With this value, we can write the partial pressure expression for each gas:

P_H_2=\frac{3}{5}*P_t_o_t_a_l

P_O_2=\frac{2}{5}*P_t_o_t_a_l

So, the answer would be <u>3/5P</u>.

I hope it helps!

5 0
3 years ago
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