A = change in v/t
= vf - vi / t
= 4.9 - 0 / 3
= 1.6 m/s^2
There arranged in energy shells each shell has a limit to how many electrons they can carry this varies with element.
Answer:
58.944 g
Explanation:
From the question given above, the following data were:
Mole of SO2 = 0.9210 mole
Mass of SO2 =?
Next, we shall determine the molar mass of SO2. This can be obtained by adding the molar mass of sulphur and oxygen together as illustrated below:
Molar mass of SO2 = 32 + (2 × 16)
= 32 + 32 = 64 g/mol
Finally, we shall determine the mass of 0.9210 mole of SO2 as follow:
Mole of SO2 = 0.9210 mole
Molar mass of SO2 = 64 g/mol
Mass of SO2 =?
Mole = mass /Molar mass
0.9210 = mass of SO2 / 64
Cross multiply
Mass of SO2 = 0.9210 × 64
Mass of SO2 = 58.944 g
Thus, the mass of SO2 is 58.944 g.
Answer:
i) for NaOH (or KOH) = 13.75 mL
ii) for
= 13.50 mL.
Explanation:
Phenolphthalein is an indicator which shows change in color when the conditions are highly basic.
Methyl orange is an indicator which shows change in color in presence of highly acidic medium.
For titration of NaOH and HCl we can use phenolphthalein but for sodium carbonate (a weak base) with HCl we use mehtyl orange.
Now in case of mixture of given strong base and weak base the reading or end point obtained from phenolphthalein, shows the neutralization of NaOH only and half neutralization of sodium carbonate.


While the reading or end point of methyl orange shows the neutralization of both the base present.
a) The volume of HCl used for phenolphthalein end point = 20.50 mL
Let us say the volume of HCl used for NaOH = V1
The volume of HCl used for half neutralization of sodium carbonate = V2
(1)
b) the volume of HCl used for methyl organe end point = 27.25
This volume of HCl used for both NaOH and Na₂CO₃
(2)
Equating equation 1 and 2

i) Thus the volume of Acid used for NaOH (Or KOH if present in place of NaOH) = 20.50-6.75= 13.75 mL
ii) the volume of acid used for sodium carbonate =
Answer:
It is referred to as b) premises liability