Which 4 elements make up the bulk of living matter?

1 answer:

4 0

"<span>Let's start with the basics: you have probably heard that your body is 90% (or 85% or 95%) water. In actual fact, water is (probably--unless you are obese) the majority of your body weight--but nowhere near 90%. The best estimate I have seen is 57% (Body water). So that puts hydrogen and oxygen in the top four.

As I mentioned, extremely obese people can be less than 50% water. Fat (triglycerides) is composed of carbon, hydrogen, and oxygen. The majority of the mass of a triglyceride is carbon--chemically it is closely related to biodiesel. So that puts carbon in the top four.

Finally, amino acids which make up proteins (which make up muscle) require nitrogen. That makes the top four.: Oxygen, Carbon, Hydrogen, and Nitrogen.

But wait! What about bones? Aren't they calcium and phosphorous? Bones are really heavy.

It turns out that calcium and phosphorous are indeed the next two most abundant (by mass) elements in the body, but where nitrogen is about 3% of your body mass, calcium and phosphorous are 1.5% and 1.2% respectively.

You can find the full breakdown of the elemental composition of your body here: <span>Abundance of the chemical elements"

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What is the H* concentration in a solution with a pH of 1.25?

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Answer:

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- Hope that helps! Please let me know if you need further explanation.

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Compare What do infrared technologies, fiber optic

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2 years ago

The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab. How many moles of dextrose is this equivalent t

Katena32 [7]

The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab the moles of dextrose is this equivalent to is 3.6888 moles.

<h3>What are moles?</h3>

A mole is described as 6.02214076 × 1023 of a few chemical unit, be it atoms, molecules, ions, or others. The mole is a handy unit to apply due to the tremendous variety of atoms, molecules, or others in any substance.

To calculate molar equivalents for every reagent, divide the moles of that reagent through the moles of the restricting reagent. The calculation is follows:

655/12 x 6 + 12+ 16 x 6
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